How to pass Json object from ajax to spring mvc controller?

Question

I am working on SpringMVC, I am passing data from ajax to controller but i got null value in my controller please check my code below

function searchText()
{
   var sendData = {
    "pName" : "bhanu",
     "lName" :"prasad"
   }
  $.ajax({
type: "POST",
 url: "/gDirecotry/ajax/searchUserProfiles.htm,
    async: true,
    data:sendData,
    success :function(result)
    {
    }
 }

MyControllerCode

         RequestMapping(value="/gDirecotry/ajax/searchUserProfiles.htm",method=RequestMethod.POST)

       public  @ResponseBody String  getSearchUserProfiles(HttpServletRequest request)
       {
         String pName = request.getParameter("pName");
         //here I got null value
       }

any one help me

what is the /gDirecotry? Is it under WEB-INF folder?

Hosein Aqajani
– Hosein Aqajani

2016-10-22 06:05:22 +00:00
Commented Oct 22, 2016 at 6:05 — Hosein Aqajani
– Hosein Aqajani, Commented Oct 22, 2016 at 6:05

Antonio112009 · Accepted Answer · 2019-09-20 11:03:16Z

52

Hey enjoy the following code.

Javascript AJAX call

function searchText() {
   var search = {
      "pName" : "bhanu",
      "lName" :"prasad"
   }

   $.ajax({
       type: "POST",
       contentType : 'application/json; charset=utf-8',
       dataType : 'json',
       url: "/gDirecotry/ajax/searchUserProfiles.html",
       data: JSON.stringify(search), // Note it is important
       success :function(result) {
       // do what ever you want with data
       }
   });
}

Spring controller code

RequestMapping(value="/gDirecotry/ajax/searchUserProfiles.htm",method=RequestMethod.POST)

public  @ResponseBody String  getSearchUserProfiles(@RequestBody Search search, HttpServletRequest request) {
    String pName = search.getPName();
    String lName = search.getLName();

    // your logic next
}

Following Search class will be as follows

class Search {
    private String pName;
    private String lName;

    // getter and setters for above variables
}

Advantage of this class is that, in future you can add more variables to this class if needed.
Eg. if you want to implement sort functionality.

edited Sep 20, 2019 at 11:03

Antonio112009

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answered Dec 30, 2013 at 7:13

Vijay Shegokar

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3 Comments

Hosein Aqajani Over a year ago

I have problem: Http status 405, Request method Get not supported

Vijay Shegokar Over a year ago

@H.Aqjn The above example is of POST request, you cannot pass post data in GET request.

J.Doe Over a year ago

thisss code saved me hehe keep helping +1

Farside · Accepted Answer · 2016-03-06 15:52:17Z

Use this method if you dont want to make a class you can directly send JSON without Stringifying. Use Default Content Type. Just Use @RequestParam instead of @RequestBody. @RequestParam Name must be same as in json.

Ajax Call

function searchText() {
    var search = {
    "pName" : "bhanu",
    "lName" :"prasad"
    }
    $.ajax({
    type: "POST",
    /*contentType : 'application/json; charset=utf-8',*/ //use Default contentType
    dataType : 'json',
    url: "/gDirecotry/ajax/searchUserProfiles.htm",
    data: search, // Note it is important without stringifying
    success :function(result) {
    // do what ever you want with data
    }
    });

Spring Controller

RequestMapping(value="/gDirecotry/ajax/searchUserProfiles.htm",method=RequestMethod.POST)

   public  @ResponseBody String  getSearchUserProfiles(@RequestParam String pName, @RequestParam String lName) {
       String pNameParameter = pName;
       String lNameParameter = lName;

       // your logic next
   }

Tech Mahesh · Accepted Answer · 2013-11-28 07:52:39Z

0

I hope, You need to include the dataType option,

dataType: "JSON"

And you could get the form data in controller as below,

 public  @ResponseBody String  getSearchUserProfiles(@RequestParam("pName") String pName ,HttpServletRequest request)
       {
         //here I got null value
       }

answered Nov 28, 2013 at 7:52

Tech Mahesh

3921 gold badge3 silver badges14 bronze badges

1 Comment

Michael Peterson Over a year ago

Jquery is going to infer json response data based on the MIME type of the controller response, so it is not required. "The type of data that you're expecting back from the server. If none is specified, jQuery will try to infer it based on the MIME type of the response (an XML MIME type will yield XML, in 1.4 JSON will yield a JavaScript object, in 1.4 script will execute the script, and anything else will be returned as a string). The available types (and the result passed as the first argument to your success callback) are: ..." api.jquery.com/jquery.ajax

Sam Kaz · Accepted Answer · 2015-12-22 01:07:31Z

0

If you can manage to pass your whole json in one query string parameter then you can use rest template on the server side to generate Object from json, but still its not the optimal approach

answered Dec 22, 2015 at 1:07

Sam Kaz

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Comments

Michael Peterson · Accepted Answer · 2018-04-02 12:49:34Z

-3

u take like this 
var name=$("name").val();
var email=$("email").val();

var obj = 'name='+name+'&email'+email;
  $.ajax({
   url:"simple.form",
   type:"GET",
   data:obj,
   contentType:"application/json",
   success:function(response){
  alert(response);
  },
  error:function(error){
  alert(error);
  }
});

spring Controller

@RequestMapping(value = "simple", method = RequestMethod.GET)
public @ResponseBody String emailcheck(@RequestParam("name") String name, @RequestParam("email") String email, HttpSession session) {

    String meaaseg = "success";
    return meaaseg;
}

edited Apr 2, 2018 at 12:49

Michael Peterson

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answered Jul 25, 2016 at 11:00

nasarreddy

1

1 Comment

Jose Pose S Over a year ago

GET with body really?

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