Regular expression required for replacing string in shell script

Question

Can anyone please help me write a shell script in linux which would replace the hostname in a particular file.

eg : I have multiple files which have certain ip addresses.

http://10.160.228.12:8001/soa-infra/services/default/AIAAsyncErrorHandlingBPELProcess/client?WSDL

http://VQAIAAPPDEV:8001/soa-infra/services/default/AIAAsyncErrorHandlingBPELProcess/client?WSDL

Basically what I would want to replace is the string between "http://" and ":8001" with any required string.

Can someone help me with this please.

Some More info:-

I want to do this iteratively across many folders. So basically it will search all the files in each folder and perform the necessary changes.

devnull · Accepted Answer · 2013-12-02 06:45:26Z

2

You could use sed. Saying:

sed -r 's|(http://)([^:]*)(:8001)|\1something\3|g' filename

would replace is the string between "http://" and ":8001" with something.

If you want to make the change to the file in-place, use the -i option:

sed -i -r 's|(http://)([^:]*)(:8001)|\1something\3|g' filename

answered Dec 2, 2013 at 6:45

devnull

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3 Comments

user3056318 Over a year ago

What if I want to iteratively check in files in many folders and do the necessary changes?

devnull Over a year ago

@user3056318 Use find. You can say: find /some/path -type f -exec sed -i -r 's|(http://)([^:]*)(:8001)|\1something\3|g' {} \;

devnull Over a year ago

@user3056318 Consider accepting the answer if it worked for you. You might also want to refer to this.

AlexiusFlavius · Accepted Answer · 2013-12-02 07:13:48Z

0

Use sed command from Linux shell

sed -i 's%OldHost%NewHost%g' /yourfolder/yourfile

answered Dec 2, 2013 at 7:13

AlexiusFlavius

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Comments

Ranjithkumar T · Accepted Answer · 2013-12-02 11:25:23Z

0

Tried with "for"

 # cat replace.txt
 http://10.160.228.12:8001/soa-     infra/services/default/AIAAsyncErrorHandlingBPELProcess/client?WSDL

 http://VQAIAAPPDEV:8001/soa-infra/services/default/AIAAsyncErrorHandlingBPELProcess/client?WSDL


 # for i in `cat replace.txt | awk -F: '{print $2}' | sed 's/^\/\///g' | sed '/^$/d'` ; do sed -i "s/$i/Your_hostname/"  replace.txt ; done

 # cat replace.txt
 http://Your_hostname:8001/soa- infra/services/default/AIAAsyncErrorHandlingBPELProcess/client?WSDL

 http://Your_hostname:8001/soa-infra/services/default/AIAAsyncErrorHandlingBPELProcess/client?WSDL

Its working for me...!

answered Dec 2, 2013 at 11:25

Ranjithkumar T

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