String pattern matching problem in Java

Question

In my program when I'm using

line.replaceAll("(", "_");

I got a RuntimeException:

 at java.util.regex.Pattern.error(Unknown Source)
 at java.util.regex.Pattern.accept(Unknown Source)
 at java.util.regex.Pattern.group0(Unknown Source)
 at java.util.regex.Pattern.sequence(Unknown Source)
 at java.util.regex.Pattern.expr(Unknown Source)
 at java.util.regex.Pattern.compile(Unknown Source)
 at java.util.regex.Pattern.<init>(Unknown Source)
 at java.util.regex.Pattern.compile(Unknown Source)
 at java.lang.String.replaceAll(Unknown Source)
 at Processing.processEarly(Processing.java:95)
 at Processing.main(Processing.java:34)

Is there any reason? How can we avoid it?

David M · Accepted Answer · 2010-01-09 11:40:55Z

37

The first argument to string.replaceAll is a regular expression, not just a string. The opening left bracket is a special character in a regex, so you must escape it:

line.replaceAll("\\(", "_");

Alternatively, since you are replacing a single character, you could use string.replace like so:

line.replace('(', '_');

edited Jan 9, 2010 at 11:40

answered Jan 9, 2010 at 11:23

David M

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1 Comment

McDowell Over a year ago

String.replace can also be used for literal (non-regex) replacement.

missingfaktor · Accepted Answer · 2010-01-09 19:29:51Z

2

The error message above the stack trace is (somewhat) helpful:

Exception in thread "main" java.util.regex.PatternSyntaxException: Unclosed group near index 1 ( ^

(That's what I get in Java 6.) It mentions "regex", "group", and the parenthesis. If you can't see this message, you should check how you're logging/catching/displaying exceptions. It could save you some trouble in the future.

edited Jan 9, 2010 at 19:29

missingfaktor

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answered Jan 9, 2010 at 11:32

Ken

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