Printing out a random string (Python)

Question

I am asked to produce a random string using a previously defined value.

THREE_CHOICES = 'ABC'
FOUR_CHOICES = 'ABCD'
FIVE_CHOICES = 'ABCDE'

import random

def generate_answers(n: int) -> str:
    '''Generates random answers from number inputted '''
    for i in range(0,n):
        return random.choice(FOUR_CHOICES)
        continue

What I am trying to get happening here is, if I were to plug in 7 into the function I'd get something like "ABDCBBA"

A random 7 character string from the specified letters. However, this code is returning only one random character no matter what number I put in (has to be non-zero).

I don't know what to do here, can someone point me in the right direction?

return is the end of your function. Always. So accumulate in some manner, and then return the accumulated value. — roippi
– roippi, Commented Dec 5, 2013 at 3:58

Serial · Accepted Answer · 2013-12-05 03:58:42Z

1

you could just return a list like this:

def generate_answers(n):
    '''Generates random answers from number inputted '''
    randoms = [random.choice(FOUR_CHOICES) for _ in range(0,n)]
    return randoms
    #return ''.join(randoms) to get string

print generate_answers(7)

this would print a list like this: ['D', 'D', 'D', 'B', 'A', 'A', 'C']

you could join the list if you want a string

answered Dec 5, 2013 at 3:58

Serial

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1 Comment

Serial Over a year ago

@EricCuevas No problem! good luck with the rest of the project :)!

Jules Gagnon-Marchand · Accepted Answer · 2013-12-05 03:58:30Z

0

not tested, but should work.

THREE_CHOICES = 'ABC'
FOUR_CHOICES = 'ABCD'
FIVE_CHOICES = 'ABCDE'

import random

def generate_answers(n):
    '''Generates random answers from number inputted '''
    answerList = ""
    for i in range(0,n):
        answerList += random.choice(FOUR_CHOICES)
    return answerList

answered Dec 5, 2013 at 3:58

Jules Gagnon-Marchand

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