Java Web Server Application

Question

I am learning how to make web applications and have just implemented a simple one that should display the current date on the web page. However, I am receiving an error while doing so. I ran it on debug mode with a breakpoint placed on: resp.getWriter().println(new Date());

Here is my Java Code:

package org.test.webapp;

import java.io.IOException;
import java.util.Date;

import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class TestServlet extends HttpServlet {

    @Override
    protected void doGet(HttpServletRequest req, HttpServletResponse resp)
            throws ServletException, IOException {
        resp.getWriter().println(new Date());
    }

}

Web.XML file:

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID" version="2.5">

    <servlet>
        <servlet-name>Test</servlet-name>
        <servlet-class>org.test.webapp/TestServlet</servlet-class>
    </servlet>

    <servlet-mapping>
        <servlet-name>Test</servlet-name>
        <url-pattern>/test</url-pattern>
    </servlet-mapping>



    <display-name>Example01</display-name>
    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
        <welcome-file>index.htm</welcome-file>
        <welcome-file>index.jsp</welcome-file>
        <welcome-file>default.html</welcome-file>
        <welcome-file>default.htm</welcome-file>
        <welcome-file>default.jsp</welcome-file>
    </welcome-file-list>
</web-app>

This is the error I am receiving:

type Exception report

message

description The server encountered an internal error () that prevented it from fulfilling this request.

exception

javax.servlet.ServletException: Error allocating a servlet instance
    org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
    org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
    org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:859)
    org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
    org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
    java.lang.Thread.run(Unknown Source)

root cause

java.lang.NoClassDefFoundError: IllegalName: org.test.webapp/TestServlet
    java.lang.ClassLoader.preDefineClass(Unknown Source)
    java.lang.ClassLoader.defineClass(Unknown Source)
    java.security.SecureClassLoader.defineClass(Unknown Source)
    org.apache.catalina.loader.WebappClassLoader.findClassInternal(WebappClassLoader.java:2818)
    org.apache.catalina.loader.WebappClassLoader.findClass(WebappClassLoader.java:1159)
    org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1647)
    org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1526)
    org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
    org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
    org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:859)
    org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
    org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
    java.lang.Thread.run(Unknown Source)

note The full stack trace of the root cause is available in the Apache Tomcat/6.0.32 logs.

The Error is when I enter: localhost:8080/Example01/test on the URL — Dheeraj
– Dheeraj, Commented Dec 8, 2013 at 21:03
I think the error is in the definition of servlet, in web.xml — HAL9000
– HAL9000, Commented Dec 8, 2013 at 21:05
By the way, if you're wanting to start working with web applications, I strongly recommend using a framework like Spring MVC instead of handling all the servlet details yourself; they can provide plumbing features like URL parsing, content negotiation, and response building for you. — chrylis -cautiouslyoptimistic-
– chrylis -cautiouslyoptimistic-, Commented Dec 8, 2013 at 21:09
Sidenote: be sure to close the writer by wrapping it in a try-finally block. Something like: PrintWriter writer = null; try { writer = resp.getWriter(); writer.println(new Date()); } finally { if( writer != null ) writer.close(); } — musical_coder
– musical_coder, Commented Dec 8, 2013 at 21:09
I am trying to create an application where you are able to convert video's to different formats where the video is saved on a web server so that the user can access it once the conversion is complete. What would you recommend as the best way of approaching this? — Dheeraj
– Dheeraj, Commented Dec 8, 2013 at 22:27

radai · Accepted Answer · 2013-12-08 21:05:58Z

3

your serlvet class should reference a class name. so instead of this:

<servlet-class>org.test.webapp/TestServlet</servlet-class>

which is an illegal class name (that your server fails to find, hence the exception), try this:

<servlet-class>org.test.webapp.TestServlet</servlet-class>

answered Dec 8, 2013 at 21:05

radai

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