pass param as xpath expressin to XSLT- javascript

Question

Looking for a solution, on the following: This is my javascript function which is setting a parameter to my xsl file and this parameter contains a string query which has a xpath syntx

queryFilter = "*/person[name='John']";

function getXSLDoc(xslDocument,xmlDocument,queryFilter) {
 ..
  var processor = new XSLTProcessor();
  processor.setParameter(null,"name",queryFilter);
....
}

Now on my xslt file I want to take queryFilter string and use it in a loop or create a variable:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
                xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
                xmlns="http://www.w3.org/1999/xhtml">
     <xsl:output method="html" indent="yes"/>

     <xsl:param name="queryFilter"/> 

<!-- Lets say I want to create a local variable and use it to loop on a node -->

    <xsl:variable name="varFilter" select="$queryFilter"/>

    <xsl:for-each select="$**varFilter**">
        <tr>
            <xsl:apply-templates select="name"/>
            ..
        </tr> 
    </xsl:for-each>

 </xsl:stylesheet>

Now how do I get to use the param i set on my javascript function as an xpath expression?

That XSLT file isn't valid. There are no templates. I'd suggest rewriting your XSLT. — user764357
– user764357, Commented Dec 9, 2013 at 4:48
Have you tried simply using the parameter as is, i.e. <xsl:for-each select="$queryFilter">? — michael.hor257k
– michael.hor257k, Commented Dec 9, 2013 at 5:29
I believe what you are trying to do is dynamic evaluation of xpath, which is not supported in XSLT 1.0 (or 2.0), I think. You can use an extension function to do this though. Check out exslt.org/dyn/index.html for example. — Tim C
– Tim C, Commented Dec 9, 2013 at 8:57

Martin Honnen · Accepted Answer · 2013-12-09 10:36:26Z

1

There is no support to evaluate a complete XPath expression dynamically at run-time. But for many cases it suffices to pass in a number or string value which you use in a comparison e.g.

name = "John";

and

processor.setParameter(null,"name",name);

and then in the XSLT you have

<xsl:param name="name"/>

and

<xsl:for-each select="*/person[name = $name]">...</xsl:for-each>

answered Dec 9, 2013 at 10:36

Martin Honnen

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