I have a number in JavaScript that I'd like to convert to a money format:
556633 -> £5566.33
How do I do this in JavaScript?
Add a comment
|
5 Answers
Try this:
var num = 10;
var result = num.toFixed(2); // result will equal string "10.00"
4 Comments
Rob Levine
+1 for ensuring 2 decimal places (plus toFixed also handles rounding)
Frederik.L
+1, to improve, you may ensure that it returns a number with a parseFloat rather than a string
Santosh
how to get the typeof to be number but still retain the trailing zero; Example parseFloat(3.6 + 4.4).toFixed(1) output to be number => 8.0 than string "8.0"
This works:
var currencyString = "£" + (amount/100).toFixed(2);
3 Comments
Spock
This returns a string... :(
Rob Levine
yes - this answer is over 14 years old. There was pretty much no numerical currency handling options back then. No ECMA internationalisation API, npm packages weren't a thing (by staggering coincidence, this answer was published on the day the first version of npm was released). Back then, if you wanted a number formatted as a currency, you did it all by yourself, by formatting the number and pre-pending the currency symbol to create a string.
Spock
sorry man, I didn't notice the age of the answer. Cheers
Try
"£"+556633/100
3 Comments
Skilldrick
I'd say
"£" + (556633 / 100) to be sure.Rob Levine
Works for this exact case, but how about if the number 556633.9 was fed in. Then it gives too many decimal places.
YOU
You are right Rob Levine, if OP want 2 decimal places, need to do .toFixed(2), but there is answers for that already, I wouldn't update my answer.
This script making only integer to decimal. Seperate the thousands
onclick='alert(MakeDecimal(123456789));'
function MakeDecimal(Number) {
Number = Number + "" // Convert Number to string if not
Number = Number.split('').reverse().join(''); //Reverse string
var Result = "";
for (i = 0; i <= Number.length; i += 3) {
Result = Result + Number.substring(i, i + 3) + ".";
}
Result = Result.split('').reverse().join(''); //Reverse again
if (!isFinite(Result.substring(0, 1))) Result = Result.substring(1, Result.length); // Remove first dot, if have.
if (!isFinite(Result.substring(0, 1))) Result = Result.substring(1, Result.length); // Remove first dot, if have.
return Result;
}
Comments
Using template literals you can achieve this:
const num = 556633;
const formattedNum = `${num/100}.00`;
console.log(formattedNum);
