Java Program for infinite loop

Question

The below code accepts an integer and checks and prints if <5, or if divisible by 5, or if divisible by 3 or if divisible by both 3 and 5. but I want to put the code into infinite looping so that the console repeatedly asks me to enter an integer after printing the output. Here is my code so far:

import java.util.Scanner;
public class Q3c {
public static void main(String args[]) {
    System.out.println("Enter an integer ");
    Scanner input = new Scanner(System.in);

    int n = input.nextInt();
    if ((n%5 == 0) && (n%3 == 0)) {
        System.out.println("The number " + n + " is  divisible by 3 and 5");
    }
    else {
        if(n%5 == 0) {
              System.out.println(n + " is divisble by 5");
        }
        if(n%3 == 0) {
              System.out.println(n + " is divisble by 3");
        }
    }

    if (n < 5) {
        System.out.println(n + "is <5");
    }
    input.close();
}
}

demo output:

Enter an integer 5
5 is divisibe by 5

Enter an integer

nhgrif · Accepted Answer · 2013-12-09 22:53:48Z

4

while(true) {
    //do stuff
}

for(;;) {
    //do stuff
}

do {
    //stuff
}while(true);

All three of these are infinite loops. If you want to exit the infinite loop based on some user input (suppose 0), you can just add:

if(n == 0) {
    break;
}

where ever you want your loop to end if they have entered 0. This code snippet works for all three infinite loop variations.

answered Dec 9, 2013 at 22:53

nhgrif

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Comments

umanganiello · Accepted Answer · 2013-12-09 22:56:47Z

0

while(true) {
    //your code
    //code to manage program exit.
}

or

for(;;) {
    //your code
    //code to manage program exit.
}

or

do {
    //your code
    //code to manage program exit.
}while(true);

answered Dec 9, 2013 at 22:56

umanganiello

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Comments

ma1069 · Accepted Answer · 2013-12-09 22:57:08Z

0

I'd suggest using else if constructs, in your case, just to simplify the code... Something like:

Scanner input=new Scanner(System.in);
while(true) {
    System.out.println("Enter an integer ");
    int n=input.nextInt();
    if((n%5==0)&&(n%3==0)){
       //stuff
    } else if (n%5==0) {
       //other stuff
    } else if (n%3==0) {
       //other
    }
}

answered Dec 9, 2013 at 22:57

ma1069

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