Regular expression works on browser but not in Node.js

Question

I have to match some strings from the given variables. Say I have variable

var x = 'elseif testing';

Now I want get value "testing" from this string. So wrote.

x.match(/^elseif(.*)/);

Late I realized sometimes I do get string:

var x = 'else if testing';

So I wrote expression to match:

x.match(/^else[\s+]if(.*)/);

This works well on browser but not in Node.js. Any reason why ?

Note that this doesn't "work well in browers" - try it, it behaves the same in browsers as in node.js - that is, it matches else if and else \t if but not elseif. The + modifier means 1 or more. You want the * modifier which means 0 or more. — slebetman
– slebetman, Commented Dec 11, 2013 at 19:18

anubhava · Accepted Answer · 2013-12-11 19:00:52Z

2

Try without double escapes and character class:

x.match(/^else\s*if(.*)/i);

Also added i for case insensitive search.

Also note [\s+] will also match a literal + since inside character class + (and many other regex special characters) is considered a literal plus.

answered Dec 11, 2013 at 19:00

anubhava

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brandonscript · Accepted Answer · 2013-12-11 19:07:24Z

0

If you're explicitly wanting to match only one or zero spaces, then:

x.match(/^else\s?if(.*)/i);

answered Dec 11, 2013 at 19:07

brandonscript

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