Constructing a hash for a jQuery each loop

Question

I run trough a couple of div's with the jQuery .each function.

With console.log I get this output

The first number on each line is a factor and the last is the sum of a multiplication

I would like to make a hash like this when the each function runs

a = {0.24: 720, 0.1: 100}

The number 0.24 as key, then sum up the the second number on each 0.24 line as value and so on.

Ideas?

Update and my solution

jQuery.fn.myFunction = function(){
 var hash = {}
  this.each(function(index, element) {
    var key = var key = $(element).attr("data-key");
    var value = $(element).attr("data-value");

    if (hash.hasOwnProperty(key)){
      hash[key] = hash[key] + value
    }else{
      hash[key] = value;
    }

    });
  console.log(hash)
}

you shoulkd post code relevant to the output you get, the each loop — A. Wolff
– A. Wolff, Commented Dec 13, 2013 at 11:55
I think that, in this case it would make it unclear. It's an easy consept. Loop and make hash. — Andreas Lyngstad
– Andreas Lyngstad, Commented Dec 13, 2013 at 13:01

A.T. · Accepted Answer · 2013-12-13 13:12:13Z

1

I assume you have key and value, though it will be better if you provide at least javascript you use.

var jsonObject = {}
function makeObject(key,value)
{
 jsonObject[key] = value + parseInt(jsonObject[key] == undefined ? 0 : jsonObject[key]);
 jsonObject[key] = value;
}

call this function in your loop, after that jsonObject will contain desired Json Object. I hope this is near your requirement.

Edit:

jsonObject[key] = value + parseInt(jsonObject[key] == undefined ? 0 : jsonObject[key])

Update: above snippet is adding the value, if there is duplicate key then it will parse down the corresponding value to integer and then add it to the already unique key present in the json object. So, If there is no duplicate key then it will simply add 0 else it will ad the value.

edited Dec 13, 2013 at 13:12

answered Dec 13, 2013 at 12:04

A.T.

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5 Comments

user1508519 Over a year ago

The only problem is that if there are duplicate keys, it will overrwrite the last value.

A.T. Over a year ago

@remyabel kindly check my edit, now the function will add value to existing key's value

RobH Over a year ago

You should add the radix parameter to parseInt. The function should also be called something else as it doesn't 'make' an object at all, it mutates one in the outer scope.

A.T. Over a year ago

@RobH yes you are right here it is not type safe but i answer OP's question accordingly as OP doesn't provide any code how he is dealing with requiement

Andreas Lyngstad Over a year ago

Thanks, this answer did push me in the right direction, even though it did not solve it. I am not really sure what this parseInt(jsonObject[key] == undefined ? 0 : jsonObject[key]) does

Vitalii Del Vorobioff · Accepted Answer · 2013-12-13 11:58:48Z

0

First of all correct your object, and make keys as string:

a = {'0.24': 720, '0.1': 100}

Second: Can you show a code snippet with yhour each loop?

answered Dec 13, 2013 at 11:58

Vitalii Del Vorobioff

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1 Comment

Andreas Lyngstad Over a year ago

No need to correct object as long as i use the [] syntax h = {1: 100, 2: 200} h.1 => SyntaxError: Unexpected number h[1] => 100

RobH · Accepted Answer · 2013-12-13 12:04:56Z

0

Here's some code to illustrate an approach you could take:

var input = [{"factor":"0.24", "value": 240},
             {"factor":"0.1", "value": 100},
             {"factor":"0.24", "value": 240},
             {"factor":"0.24", "value": 240}];

var result = {};
for (var i = 0; i < input.length; i++) {
    var current = input[i];
    if (typeof result[current.factor] === 'undefined') {
        result[current.factor] = current.value;
    } else {
        result[current.factor] += current.value;
    }
}

console.log(result);

seen here: http://jsfiddle.net/6ZA4f/

Hopefully you can apply this idea to your own code.

answered Dec 13, 2013 at 12:04

RobH

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