JavaScript IF / ELSE error - expected an identifier

Question

I'm trying to learn JavaScript on Code Academy I am facing the following syntax problem. Tells me:

expected an identifier and instead saw 'else'. Missing ';' before statement

Here is the code:

If("Jon".length * 2 / (2+1) === 6);

{
    console.log("The answer makes sense!");

} 
else {

    console.log("Error. Error. Error.");
}

sidenote: console.log is not cross-browser. Old browsers will result in JavaScript error. — Raptor
– Raptor, Commented Dec 16, 2013 at 10:55
@ShivanRaptor He says he's working on codecademy so don't worry... — RobDil
– RobDil, Commented Dec 16, 2013 at 10:56

Adam Arold · Accepted Answer · 2013-12-16 10:53:21Z

2

Omit the ; in If("Jon".length * 2 / (2+1) === 6);

The syntax of if is:

if(condition) {
  // what to happen
} else {
  // what to happen
}

answered Dec 16, 2013 at 10:53

Adam Arold

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Comments

Benubird · Accepted Answer · 2013-12-16 10:53:16Z

0

Remove the semicolon from the if statement.

answered Dec 16, 2013 at 10:53

Benubird

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Comments

ajtrichards · Accepted Answer · 2013-12-16 10:53:33Z

0

You have a semicolon ; after you if statement. Remove it. It should be:

if("Jon".length * 2 / (2+1) === 6) {

   console.log("The answer makes sense!");

} else {

    console.log("Error. Error. Error.");

}

The correct usage of the if syntax is:

if (condition) {
   // Do something here
} else {
   // For instances where the condition hasn't met do something else
}

answered Dec 16, 2013 at 10:53

ajtrichards

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Comments

zzlalani · Accepted Answer · 2013-12-16 10:53:48Z

0

remove ; from

If("Jon".length * 2 / (2+1) === 6);

answered Dec 16, 2013 at 10:53

zzlalani

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Comments

Yagnesh Agola · Accepted Answer · 2013-12-16 10:54:00Z

0

Remove semicolon ; at the end of if statement.

Change

If("Jon".length * 2 / (2+1) === 6);

To

if("Jon".length * 2 / (2+1) === 6)

answered Dec 16, 2013 at 10:54

Yagnesh Agola

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Comments

Bas van Dijk · Accepted Answer · 2013-12-16 10:54:13Z

0

The if is in lowercase, and you need to remove the semicolon at the end of the if line.

if("Jon".length * 2 / (2+1) === 6) {
    console.log("The answer makes sense!");
} else {

    console.log("Error. Error. Error.");
}

answered Dec 16, 2013 at 10:54

Bas van Dijk

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Comments

Vogel612 · Accepted Answer · 2013-12-16 10:54:17Z

0

you have a semicolon to much. it should be:

if (boolean statement) {
//do sth
}
else { }

currently your if statement ends directly after the boolean statement

answered Dec 16, 2013 at 10:54

Vogel612

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2 Comments

Felix Tetteh Over a year ago

That's helpful Vogel612

Vogel612 Over a year ago

@user3106983 you don't actually need to thank everyone who posted an answer.. people who post answer generally assume they are helpful. you should only comment, if that is not the case, but also give the reasons why then. they can improve their answer if you do it right, and it probably helps then

Sence · Accepted Answer · 2013-12-16 10:54:55Z

0

remove the semicolon behind

if("Jon".length * 2 / (2+1) === 6)**;**

additional write in in lower characters

answered Dec 16, 2013 at 10:54

Sence

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Comments

JimmyK · Accepted Answer · 2013-12-16 10:57:05Z

0

Semicolons in JavaScript are used to seperate statements!

In that case, remove the semicolon from this line and ensure if is in lowercase:

if("Jon".length * 2 / (2+1) === 6);

Comments

Arun Chandran Chackachattil · Accepted Answer · 2013-12-16 10:59:57Z

0

A semicolon (;) separates JavaScript statements.

Normally you add a semicolon at the end of each executable statement.

Using semicolons also make it possible to write many statements on one line.

You have to remove the semicolon in your if statement.

Change your code

From

If("Jon".length * 2 / (2+1) === 6);

To

If("Jon".length * 2 / (2+1) === 6)

And please check out if.. else statement in javascript.

answered Dec 16, 2013 at 10:59

Arun Chandran Chackachattil

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Comments

Rubens · Accepted Answer · 2013-12-16 11:11:32Z

0

You may try this:

If ("Jon".length * 2 / (2+1) == 6) {
    console.log("The answer makes sense!");
} else {    
    console.log("Error. Error. Error.");
}

edited Dec 16, 2013 at 11:11

Rubens

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answered Dec 16, 2013 at 10:53

Sai Avinash

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