This is more a question of semantics than anything else.
I'd like to check if a variable is either one of two values. The easiest way of doing this would be:
if var == "foo" || var == "bar"
# or
if var == 3 || var == 5
But this doesn't feel very DRY to me. I know I can use String.match(), but that doesn't work for non-string variables and is three times slower.
Is there a better way of checking a variable against two values?
Put all values into an array and then it should be easy.
%w[foo bar].include?('foo') # => true
[3,5].include?(3) # => true
The case statement seems to do what you want.
case var
when "foo", "bar" then case1()
end
case var
when 3, 5 then case2()
end
The array-based methods seem likely to be slower than this.
#=== for each when statement, so this will be the same as if ["foo", "bar"] === var then case1(); elsif [3,5] === var then case2(); end
.include? method, and case was slightly faster. Not enough to make a compelling argument, though.
if [1,2].include?(1). I agree that case works very well as a replacement for multiple if and elsif statements, but not for something simple like this.You could do:
%W(foo bar baz).include? var
Or:
[3, 5].include? var
