Change a string with javascript

Question

I'm checking a string with this regular expression:/^[SE]*[\s]*[0-9]{3}[\s\-]*[0-9]{2}$/. This allows a total of 9 different formats, being: XXXXX, XXX-XX, XXX XX, SEXXXXX, SEXXX-XX, SEXXX XX, SE XXXXX, SE XXX-XX and SE XXX XX (X:s being any number from 0-9). How do I change the format to XXXXX after the check passes for one of the 9 valid formats?

I've read a bunch of other threads about the string.replace()-method but I can't seem to make it work. Here's my code so far:

        var pcValue = postalCode.value;
        var format = /^[SE]*[\s]*[0-9]{3}[\s\-]*[0-9]{2}$/;

        if (format.test(pcValue) === true) {
            pcValue = pcValue.replace(/\[SE]*[\s]*[\s\-]*$/, /^[0-9]{5}$/);
        }

What it gives me is a string with /^[0-9]{5}$/ instead of the XXXXX format I wanted.

Denys Séguret · Accepted Answer · 2013-12-18 09:58:53Z

1

You can do this :

var format = /^([SE]*)\s*(\d{3})[\s\-]*(\d\d)$/;
if (format.test(pcValue)) {
    pcValue = pcValue.replace(format, "$2$3");
}

Note that if you don't do anything else than replacing if test returns true, then you don't have to test at all, just execute the replacement.

edited Dec 18, 2013 at 9:58

answered Dec 18, 2013 at 9:51

Denys Séguret

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2 Comments

Lemonmuncher Over a year ago

It works but if there is a SE at the beginning it's still there after the replacement. How do i remove it aswell?

Denys Séguret Over a year ago

@Lemonmuncher Edited to remove the SE

Stephan · Accepted Answer · 2013-12-18 09:57:24Z

0

Try this:

var pcValue = postalCode.value;
pcValue = pcValue.replace(/^[SE]*[\s]*([0-9]{3})[\s\-]*([0-9]{2})$/, "$1$2");

Demo http://jsfiddle.net/uLJEm/

answered Dec 18, 2013 at 9:57

Stephan

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1 Comment

Lemonmuncher Over a year ago

Worked like a charm! Even removed the eventual SE's.

Kristoffer Sall-Storgaard · Accepted Answer · 2013-12-18 10:18:57Z

0

var pcValue = postalCode.value;
var format = /^[SE]*[\s]*[0-9]{3}[\s\-]*[0-9]{2}$/;

if (format.test(pcValue) === true) {
    pcValue = pcValue.replace(/\[SE]*[\s]*[\s\-]*$/, /^[0-9]{5}$/);
}

str.replace(original,replicant);

edited Dec 18, 2013 at 10:18

Kristoffer Sall-Storgaard

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answered Dec 18, 2013 at 9:53

ProllyGeek

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Comments

score 0 · Accepted Answer · 2013-12-22 07:05:06Z

The answer you've marked as accepted also validates these kinds of inputs :

"ES 12345"
"SSSSS 123 -  45"
"SESE     123---45"

The following regular expression might better fit with your needs :

function parse(input) {
    var re = /^(?:SE)?\s?(\d{3})(?:\s|-)?(\d\d)$/;
    return re.test(input) && input.replace(re, '$1$2');
}

var input1 = parse('SE 123 45'); // 12345
var input2 = parse('ES 123 45'); // false
input1 || alert('Please fix input #1!');
input2 || alert('Please fix input #2!'); // alert!

A little help about /^(?:SE)?\s?(\d{3})(?:\s|-)?(\d\d)$/ :

^...$       string boundaries
(...)       capture match
(?:...)     don't capture match

(?:SE)?     "SE", zero or one time
\s?         a whitespace, zero or one time
(\d{3})     3 digits (captured -> $1)
(?:\s|-)?   a whitespace or a dash, zero or one time
(\d\d)      2 digits (captured -> $2)

More on regular expressions : http://www.javascriptkit.com/javatutors/redev.shtml.

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