When I type a number with prompt var myNumber = parseInt(prompt("..."))I want it to be converted into an array of numbers. When I try with myNumber = myNumber.split("") it returns:
Object 1 has no method 'split'
help me please
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2What are you using to delimit the numbers in the prompt? You can't split a number, you split strings.Ben Taber– Ben Taber2013-12-22 14:21:20 +00:00Commented Dec 22, 2013 at 14:21
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Why don't you convert to number after split?Ringo– Ringo2013-12-22 14:22:49 +00:00Commented Dec 22, 2013 at 14:22
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I didn't know that i can't split() a number.user3127052– user31270522013-12-22 14:23:51 +00:00Commented Dec 22, 2013 at 14:23
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4 Answers
You cannot split the int, you need to have a string data type for this code to work!
So, I would like to suggest to first split it and then convert it to int as
var numbers = "1, 2, 3";
var eachNumber = numbers.split(",");
/* now parse them or whatso ever */
This will work, as you're just splitting the string. And then you will parse it just the way you did it in the first method (of yours).
answered Dec 22, 2013 at 14:24
Afzaal Ahmad Zeeshan
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2 Comments
user3127052
i should have thought about making another var where I split the firts var. thank you Afzaal!
Afzaal Ahmad Zeeshan
yes, you could have done that! :) However, you're most welcome .. :)
var intArray = prompt("...").split(" ").map(Number);
1 Comment
Paul S.
You can shorten your
map by simply writing .map(Number), try it outYou would need to change the number to string, then split it.
You would then want to return it to an integer.
var myNumber = parseInt(prompt("Enter your number"));
var tempString = myNumber + "";
var arr = tempString.split("");
console.log(arr);
Here is a fiddle - http://jsfiddle.net/kellyjandrews/Wa5zD/
Comments
myNumber is an integer variable, which does not hold .split() method, it belongs to string variable.
var no = "12 13 14 15";
var noV = no.split(" ")
