Laravel Eloquent inner join with multiple conditions

Question

I have a question about inner joins with multiple on values. I did build my code like this in laravel.

public function scopeShops($query) {
    return $query->join('kg_shops', function($join)
    {
        $join->on('kg_shops.id', '=', 'kg_feeds.shop_id');
        // $join->on('kg_shops.active', '=', "1"); // WRONG
        // EDITED ON 28-04-2014
        $join->on('kg_shops.active', '=', DB::raw("1"));

    });
}

Only problem is, it gives this outcome:

Column not found: 1054 Unknown column '1' in 'on clause' (SQL: select `kg_feeds`.* from `kg_feeds` inner join `kg_shops` on `kg_shops`.`id` = `kg_  
  feeds`.`shop_id` and `kg_shops`.`active` = `1`) (Bindings: array (                                                                                        ))

As you can see, the multiple conditions in the join go fine, but it thinks the 1 is a column instead of a string. Is this even possible, or do I have to fix it in the where.

rama · Accepted Answer · 2013-12-24 17:58:30Z

88

return $query->join('kg_shops', function($join)
 {
   $join->on('kg_shops.id', '=', 'kg_feeds.shop_id');

 })
 ->select('required column names') 
 ->where('kg_shops.active', 1)
 ->get();

answered Dec 24, 2013 at 17:58

rama

9126 silver badges2 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Ricard Espinàs Llovet Over a year ago

You can add the where clause inside the join, so eloquent it will think that "1" is not a column, as Kamlesh says.

Majbah Habib · Accepted Answer · 2016-08-01 09:51:39Z

73

You can see the following code to solved the problem

return $query->join('kg_shops', function($join)
{
    $join->on('kg_shops.id', '=', 'kg_feeds.shop_id');
    $join->where('kg_shops.active','=', 1);
});

Or another way to solved it

 return $query->join('kg_shops', function($join)
{
    $join->on('kg_shops.id', '=', 'kg_feeds.shop_id');
    $join->on('kg_shops.active','=', DB::raw('1'));
});

answered Aug 1, 2016 at 9:51

Majbah Habib

8,6064 gold badges41 silver badges42 bronze badges

3 Comments

irfanengineer Over a year ago

If i'm print query log then it is showing AND between both condition. But how I can use or instead of AND

Majbah Habib Over a year ago

Use it. $join->orOn('kg_shops.active','=', DB::raw('1'));

Anees Sadeek Over a year ago

If the 'active' field contains a string, you have to use DB::raw("'YES'") instead of DB::raw('YES').

Yagnesh bhalala · Accepted Answer · 2018-06-16 08:51:55Z

37

//You may use this example. Might be help you...

$user = User::select("users.*","items.id as itemId","jobs.id as jobId")
        ->join("items","items.user_id","=","users.id")
        ->join("jobs",function($join){
            $join->on("jobs.user_id","=","users.id")
                ->on("jobs.item_id","=","items.id");
        })
        ->get();
print_r($user);

answered Jun 16, 2018 at 8:51

Yagnesh bhalala

1,3251 gold badge17 silver badges17 bronze badges

Comments

The Alpha · Accepted Answer · 2014-04-30 06:02:08Z

23

Because you did it in such a way that it thinks both are join conditions in your code given below:

public function scopeShops($query) {
    return $query->join('kg_shops', function($join)
    {
        $join->on('kg_shops.id', '=', 'kg_feeds.shop_id');
        $join->on('kg_shops.active', '=', "1");
    });
}

So,you should remove the second line:

return $query->join('kg_shops', function($join)
{
    $join->on('kg_shops.id', '=', 'kg_feeds.shop_id');
});

Now, you should add a where clause and it should be like this:

return $query->join('kg_shops', function($join)
{
  $join->on('kg_shops.id', '=', 'kg_feeds.shop_id')->where('kg_shops.active', 1);
})->get();

edited Apr 30, 2014 at 6:02

answered Dec 22, 2013 at 18:12

The Alpha

147k30 gold badges294 silver badges313 bronze badges

3 Comments

Wouter Neuteboom Over a year ago

Hi Sheikh,Thanks for the answer but I tried that. Gives me the following result. PHP Fatal error: Call to undefined method Illuminate\Database\Query\JoinClause::where() in /app/models/Feeds.php on line 35

Saani Over a year ago

How can I add more than one join with OR condition? like join On this OR join ON that?

The Alpha Over a year ago

$join->on()->orOn().

Kamlesh · Accepted Answer · 2019-04-19 08:20:10Z

12

You can simply add multiple conditions by adding them as where() inside the join closure

->leftJoin('table2 AS b', function($join){
        $join->on('a.field1', '=', 'b.field2')
        ->where('b.field3', '=', true)
        ->where('b.field4', '=', '1');
})

answered Apr 19, 2019 at 8:20

Kamlesh

6,2591 gold badge51 silver badges55 bronze badges

Comments

ThangTD · Accepted Answer · 2016-04-25 10:08:41Z

11

More with where in (list_of_items):

    $linkIds = $user->links()->pluck('id')->toArray();

    $tags = Tag::query()
        ->join('link_tag', function (JoinClause $join) use ($linkIds) {
            $joinClause = $join->on('tags.id', '=', 'link_tag.tag_id');
            $joinClause->on('link_tag.link_id', 'in', $linkIds ?: [-1], 'and', true);
        })
        ->groupBy('link_tag.tag_id')
        ->get();

    return $tags;

Hope it helpful ;)

edited Apr 25, 2016 at 10:08

answered Apr 25, 2016 at 8:16

ThangTD

1,70419 silver badges17 bronze badges

7 Comments

Ash Over a year ago

Instead of using array_map you can do: $linkIds = $links->lists('id', 'id') Also if you have eloquent models using hasMany() with pivot() works well too.

ThangTD Over a year ago

ok very thank for your suggest, I have not found it for a long :(

Ash Over a year ago

Sometimes things may not be documented but I tend to look at the source code on Github or the API documentation

ThangTD Over a year ago

:D me too, I will try to reduce unnecessary codes like this, actually I lost time to dig a function like you gave but quited :(

Ash Over a year ago

It's just an alias for pluck it doesn't work once you have used get; so in your case $linkIds = $user->links()->pluck('id')

|

Uncoke · Accepted Answer · 2019-09-03 06:22:38Z

6

This is not politically correct but works

   ->leftJoin("players as p","n.item_id", "=", DB::raw("p.id_player and n.type='player'"))

answered Sep 3, 2019 at 6:22

Uncoke

1,9224 gold badges33 silver badges63 bronze badges

Comments

pirix · Accepted Answer · 2023-04-27 07:27:01Z

2

this is it works. You don't have to use $param. I wrote it this way as an example. If you want, you can just write the value in the condition.

public function scopeShops($query){
    $param = 1;
    return $query->join('kg_shops', function ($join) use ($param) {
        $join->on('kg_shops.id', '=', 'kg_feeds.shop_id')
            ->where('kg_shops.active', '=', $param);
    });
}

edited Apr 27, 2023 at 7:27

answered Apr 27, 2023 at 7:24

pirix

212 bronze badges

Collectives™ on Stack Overflow

Laravel Eloquent inner join with multiple conditions

8 Answers 8

1 Comment

3 Comments

Comments

3 Comments

Comments

7 Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

8 Answers 8

1 Comment

3 Comments

Comments

3 Comments

Comments

7 Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related