preg_replace to preg_replace_callback with an array as replacement

Question

I'm migrating an application to work with PHP 5.5, and I need to remove the /e character from the preg_replace function, to do that I'm using preg_replace_callback()

My actual function looks like this:

preg_replace ( '#\{([a-z0-9\-_]*?)\}#Ssie' , '( ( isset($array[\'\1\']) ) ? $array[\'\1\'] : \'\' );' , $template );

Where:

$template contains a html document with tags like this one: {user_name}

and $array contains

$array['user_name'] = 'The user';

I've been trying to convert this to work with PHP 5.5 with not success.

This is what I did so far:

return preg_replace_callback ( '#\{([a-z0-9\-_]*?)\}#Ssi' , function ( $array ) {
    return ( ( isset ( $array[1] ) ) ? $array[1] : '' );
} , $template );

But It's not working. The tags closed in braces are not being replaced.

What Am I missing?

fire · Accepted Answer · 2013-12-23 15:57:18Z

1

You need to use the use keyword to pull in $array into your anonymous function...

return preg_replace_callback ( '#\{([a-z0-9\-_]*?)\}#Ssi' , function ($matches) use ($array) {
    return ( ( isset ( $array[$matches[1]] ) ) ? $array[$matches[1]] : '' );
} , $template );

answered Dec 23, 2013 at 15:57

fire

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2 Comments

Lucas Over a year ago

Thanks a lot! Works perfect! I'd tried with use but I miss this: $array[$matches[1]]

J. Scott Elblein Over a year ago

@fire How would you do this using a single array, passing array_keys($preg) as the Search param, and array_values($preg) as the callback array? This causes an error:

$body = preg_replace_callback (array_keys($preg), function ($matches) use (array_values($preg)) { return ((isset($array[$matches[1]])) ? $array[$matches[1]] : ''); },$body);

Example: sandbox.onlinephpfunctions.com/code/…

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