How I can pass multiple parameters to URL in php

Question

I have a problem in passing 2 parameters via URL I don't know how, so I wrote this:

<form method="get" >
   <b>Enter the Quantity you want:</b>
   <input type="text" name="quantity">
</form>

<br><br>

<a href='./shopping-cart.php?part_id="<?php echo $_GET['part_id']; ?>"&quantity="<?php echo $_GET['quantity']; ?>"'>
   <img src="add_to_shopping_cart.png">
</a>

$_GET['part_id'] this var from another URL and I want to pass it again and $_GET['quantity'] quantity from form.

In your form add <input type="hidden" name="part_id" value="<?php echo $_GET['part_id']; ?>"/> — M Khalid Junaid
– M Khalid Junaid, Commented Dec 23, 2013 at 20:18
Your form should also have an action attribute. And there might be a problem with the quotes. — giannis christofakis
– giannis christofakis, Commented Dec 23, 2013 at 20:25

user4035 · Accepted Answer · 2013-12-23 20:29:09Z

1

You must use urlencode function for your parameters, and don't use the double quotes:

<a href='./shopping-cart.php?part_id=<?php echo urlencode($_GET['part_id']); ?>&quantity=<?php echo urlencode($_GET['quantity']); ?>'>

Even though, I suggest you to avoid long urls and use POST with hidden fields.

answered Dec 23, 2013 at 20:29

user4035

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2 Comments

Abeer Over a year ago

thank you for your help but I still have the same problem ( ( ! ) Notice: Undefined index: quantity in C:\wamp\www)

user4035 Over a year ago

@black This notice means, that $_GET['quantity'] element is undefined. It has nothing to do with the link. To avoid the notice, use the yannis hristofakis suggested.

giannis christofakis · Accepted Answer · 2013-12-23 22:17:02Z

0

You get this notice Undefined index: quantity cause you are trying to access an undefined variable. If your page url is something like page_name.php?quantity=5 then $_GET['quantity] is set, otherwise it isn't.

You should check if the $_GET variable exist. If so, use @user4035 answer to print the url.

if(isset($_GET['quantity']))
{ 
    //html code,the url
    //echo $_GET['quantity']
}

edited Dec 23, 2013 at 22:17

answered Dec 23, 2013 at 20:47

giannis christofakis

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Comments

C_B · Accepted Answer · 2013-12-23 20:45:25Z

0

There's a few errors that I can see.

You can't use $_GET['quantity'] if the user is entering it in without reloading the page (Remember, PHP is not client-side). Thus, I suggest using JavaScript for that.

Javascript:

function buildUrl(a) {
   var qty = document.getElementById("qty").value; 
   a.href = "./shopping-cart.php?part_id="+<?php echo $_GET['part_id']; ?>
   +"&quantity="+qty;
}

As you no longer need to get a PHP variable from the current page, the form is obsolete and a simple link will do.

HTML:

<b>Enter the Quantity you want:</b>
<input type="text" name="quantity">
<a href='#' onclick="buildUrl(this);"> //onclick attribute triggers the JavaScript
    <img src="add_to_shopping_cart.png">
</a>

answered Dec 23, 2013 at 20:45

C_B

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3 Comments

C_B Over a year ago

Could I have an explanation as to why I was down-voted?

giannis christofakis Over a year ago

Although you answer is very good,I think you shouldn't point him to a client side solution. He is missing fundamentally things such as POST-GET request,and an answer such as your will only make things more difficult for him. Consider that he might don't even know javascript. If you think my vote is unjustified you can edit you answer and I will undo.

C_B Over a year ago

@yannishristofakis that's a fair point, I'll leave it up though in case someone would like to try it this way.

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