I am trying to find the index of a sub-list return the value with the same index of another sub-list. I keep on running into a problem when I have duplicates, since it just returns the lowest index.
lines = [ [ 1 , 1], [3, 4] ]
x = 0
while x < (len(lines)-1):
for ch in lines[x]:
print lines[x+1][lines[x].index(ch)]
x += 1
I wanted to get an output of
3
4
but I am getting
3
3
I think I understand. In both iteration so the for loop ch is 1 so lines[x].index(ch) will be 1. Why not just loop through the second in a more straight forward fashion:
lines = [ [ 1 , 1], [3, 4] ]
x = 0
y=0
while x < (len(lines)-1):
while y < len(lines[x]):
print lines[x+1][y]
y= y+1
x = x+1
You should change your len(lines)-1 by len(lines) in the while statement, because i think it doesnt tests all the values.
index() finds the first occurence of the passed element of the list, so whenever you call [1,1].index[1], you will always get 0.
If your goal is to simply access the item of list b from the index in list a-
a = [1,1]
b = [3,4]
for x in range(0,len(a)):
print b[x]
lines[1]? For each item inlines[0], you're wanting to find the index of that occurrence of the item (not the first occurrence), and return the corresponding item fromlines[1]. But the sequence of indices that will generate is just 0, 1, 2, ...