Here is my code:
#!/bin/bash
echo "Letter:"
read a
if [ $a = "a" ]
then
echo "LOL"
fi
if [ $a = "b" ]
then
echo "ROFL"
fi
Is there a way for me to loop this so that, after displaying either LOL or ROFL, I would be asked for a letter again?
Yes.
Oh, you want to know how?
while true; do
echo "Letter:"
read a
if [ $a = "a" ]
then
echo "LOL"
elif [ $a = "b" ]
then
echo "ROFL"
fi
done
Of course, you probably want some way to get out of that infinite loop. The command to run in that case is break. I would write the whole thing like this:
while read -p Letter: a; do
case "$a" in
a) echo LOL;;
b) echo ROFL;;
q) break;;
esac
done
which lets you exit the loop either by entering 'q' or generating end-of-file (control-D).
Don't forget that you always want -r flag with read.
Also there is a quoting error on that line:
if [ $a = "a" ] # this will fail if a='*'
So here is a bit better version(I've also limited the user to input only 1 character):
#!/bin/bash
while true; do
read -rn1 -p 'Letter: ' a
echo
if [[ $a = 'a' ]]; then
echo "LOL"
elif [[ $a = 'b' ]]; then
echo "ROFL"
else
break
fi
done
Or with switch statement:
#!/bin/bash
while read -rn1 -p 'Letter: ' a; do
echo
case $a in
a) echo LOL;;
b) echo ROFL;;
*) break;;
esac
done
