org.json unreported exception while creating a JSONObject

Question

Can anyone help me understand what is going wrong?

unreported exception org.json.JSONException; must be caught or declared to be thrown
    jsonObj = new JSONObject("{\"count\":3939,\"has_more\":true,\"map_location\":{\"lat\":0.60996950000000183,\"lon\":-27.568517000000003,\"panoramio_zoom\":16},\"photos\":[{\"height\":375,}]}"); //creates the JSON object from the jsonString, for parsing
              ^

1 error

I'm using org.json, and I think I have everything set up correctly. I'm trying to create a JSONObject using the constructor in org.json that takes a source string, and I keep getting this exception. I'm not sure what is wrong with the string that I am sending in. Thanks

You need to read up on what checked exceptions are in Java - it will clear up this situation for you. Note that this is a compile error, which means it has nothing to do with the string you're passing in. — Chris Hayes
– Chris Hayes, Commented Dec 28, 2013 at 7:00

gotwo · Accepted Answer · 2020-07-08 04:40:39Z

18

Catch your Exception by creating try and catch:

try {
    JSONObject jsonObj = new JSONObject("{\"count\":3939,\"has_more\":true,\"map_location\":{\"lat\":0.60996950000000183,\"lon\":-27.568517000000003,\"panoramio_zoom\":16},\"photos\":[{\"height\":375,}]}");          
    System.out.println(jsonObj);
} catch (JSONException e) {
    //some exception handler code.
}

Or either throws your exception to caller method:

public String yourMethod(String jsonString) throws JSONException

edited Jul 8, 2020 at 4:40

gotwo

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answered Dec 28, 2013 at 7:04

Yagnesh Agola

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Jigar Joshi · Accepted Answer · 2013-12-28 06:59:48Z

2

constructor declares to throw org.json.JSONException so you must handle it (catch & handle or rethrow to let caller handle it)

answered Dec 28, 2013 at 6:59

Jigar Joshi

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