Getting String Pattern

Question

i have an example of the following string (all this in one string).

6 x 9 + 4 = 58.0 

</br> 58.0  markers cost $33.

</br> 33/ 58.0  = 0.5689655172413793 

<br>Each marker cost $0.5689655172413793 .

<br> 0.5689655172413793  x 9 = 5.120689655172414 

<br>Each eraser cost $5.120689655172414 

<br> (5.120689655172414  x 3) +  (0.5689655172413793  x 10) = 21.051724137931036 

<br>The total cost is $21.051724137931036 .

I want to remove all the other stuff and get only the mathematical expressions..

6 x 9 + 4 = 58.0
33/ 58.0  = 0.5689655172413793 
0.5689655172413793  x 9 = 5.120689655172414 
(5.120689655172414  x 3) +  (0.5689655172413793  x 10) = 21.051724137931036

I have tried the regex pattern to remove all the other stuff but it get splitted indvidually one char by one char.

 Matcher matcher = Pattern.compile("(\\d+|[\\+\\-*/=()])").matcher(qalist.get(i).getFullsol());

         while(matcher.find())
         {
             System.out.println(matcher.group(0));
         }

Anyone can help? :)

Encountered Problem

 Matcher matcher = Pattern.compile("\\(?(\\d+(?:\\.\\d+)?[^=:a-wyz]+)=\\s*(\\d+(?:\\.\\d+)?)").matcher("The expression is (9 * 1) -1 = 8 ");

I will get :

Expression: 9 * 1) -1

Answer: 8

Wonder whats wrong..

Whole expression: (5.120689655172414  x 3) +  (0.5689655172413793  x 10) = 21.051724137931036
Expression: 5.120689655172414  x 3) +  (0.5689655172413793  x 10)
Answer: 21.051724137931036

What is about read char by char and let thru all but letters, <, >, $ ... — PeterMmm
– PeterMmm, Commented Jan 1, 2014 at 10:54

Jerry · Accepted Answer · 2014-01-01 10:51:56Z

1

You could perhaps use this pattern:

\\(?\\d+(?:\\.\\d+)?[^=a-wyz]+=\\s*\\d+(?:\\.\\d+)?

regex101 demo

\\(? is to match a potential opening parenthesis

\\d+(?:\\.\\d+)? is to match a number, integer or floating.

[^=a-wyz]+= will match almost anything except equal sign and letters (x will match however) except letters until it reaches an equal sign.

\\s*\\d+(?:\\.\\d+)? is to match the result of the expression, consisting of potential spaces, and a number (integer or floating).

answered Jan 1, 2014 at 10:51

Jerry

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20 Comments

gonggong Over a year ago

Hi Jerry your codes works wonders for most of my answer templates. However i have one answer template that looks like this. I have edited from my post

Jerry Over a year ago

@rushh05 I cannot see the answer template :(

gonggong Over a year ago

To Jerry...I have a template that looks like this... It just seem to have the extra 1:, 2:, 3: infront. How do i remove it? :) Step1:7 - 1 = 6 Step2: 6/7*6 = 306 Step 3: 306 - 19 = 287

gonggong Over a year ago

And the answer shows as..... 1: 7 - 1 = 6 2: 6/7*6 = 306 3: 306 - 19 = 287

Jerry Over a year ago

@rushh05 Oh! You can add : to the negated class! Change [^=a-wyz] to [^=:a-wyz]. If you encounter similar problems, you could add characters which shouldn't be there inside.

|

Evgeniy Dorofeev · Accepted Answer · 2014-01-01 11:05:51Z

0

try this

    StringBuilder sb = new StringBuilder();
    for (String l : str.split("</?br>")) {
        l = l.trim();
        if (!l.isEmpty() && !l.matches(".*[a-zA-Z&&[^x]].*")) {
            sb.append(l).append("\n");
        }
    }

answered Jan 1, 2014 at 11:05

Evgeniy Dorofeev

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Comments

Toto · Accepted Answer · 2014-01-01 11:42:16Z

0

How about:

([()\s\d.x*+/-]+\s*=\s*[\d.]+)

answered Jan 1, 2014 at 11:42

Toto

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2 Comments

gonggong Over a year ago

I got error when i put it as ("([()\s\d.x*+/-]+\s*=\s*[\d.]+)")

gonggong Over a year ago

Its okay M42. :) thanks for the effort. Appreciate it :)

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