Get base url using jquery

Question

I have a url http://xyz.in/pqr/v/index.php and I want to get only http://xyz.in/pqr/v/ so how can I remove index.php from url.

possible duplicate of JS: Most optimized way to remove a filename from a path in a string? — NeoNexus DeMortis
– NeoNexus DeMortis, Commented Jan 2, 2014 at 7:35
@RoyiNamir then use what's left on the array: var arr = url.split('/); arr.pop(); arr = arr.join('/'); — Kroltan
– Kroltan, Commented Jan 2, 2014 at 7:41

CJ Ramki · Accepted Answer · 2014-01-02 07:44:24Z

6

Try this.

  var host = window.location.protocol+'//'+window.location.host+'/'
  alert(host);

if you want to avoid '/' at last, You can use this

var host2 = window.location.protocol+'//'+window.location.host

SEE THIS FIDDLE DEMO

edited Jan 2, 2014 at 7:44

answered Jan 2, 2014 at 7:38

CJ Ramki

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1 Comment

yashhy Over a year ago

but how will you get /pqr/v/ paths as mentioned in the question?

A.T. · Accepted Answer · 2014-01-02 07:40:32Z

3

This is the simplest way to get base url:

window.location.origin

answered Jan 2, 2014 at 7:40

A.T.

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Comments

yashhy · Accepted Answer · 2014-01-03 04:50:44Z

2

you can use .replace() function

try with this FIDDLE

var getUrl  = "http://xyz.in/pqr/v/index.php";
var change = getUrl.replace('index.php','');

NOTE : If your 'index.php' name is static

edited Jan 3, 2014 at 4:50

answered Jan 2, 2014 at 7:36

yashhy

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Comments

Ravi · Accepted Answer · 2014-01-02 07:35:16Z

0

try this

function GetBaseUrl() {
    try {
        var url = location.href;

        var start = url.indexOf('//');
        if (start < 0)
            start = 0 
        else 
            start = start + 2;

        var end = url.indexOf('/', start);
        if (end < 0) end = url.length - start;

        var baseURL = url.substring(start, end);
        return baseURL;
    }
    catch (arg) {
        return null;


  }
}

answered Jan 2, 2014 at 7:35

Ravi

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Comments

Royi Namir · Accepted Answer · 2014-01-02 07:43:23Z

0

Try this

var a='http://xyz.in/pqr/v/index.php';
alert(a.substring(0,a.lastIndexOf("/"))); //http://xyz.in/pqr/v"

answered Jan 2, 2014 at 7:43

Royi Namir

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