getting different random numbers in a loop not random

Question

I am filling an array with random numbers with a loop, but the random number is exactly the same for each item in the array, I think this is because of the seed value that Math.rand() uses. How can i get a different number each time?

for(var i = 0; i < 10; i++){
    number[i] = getRandom(0, 100);
}

function getRandom(a, b){
    var num = Math.floor((Math.random()*b)+a);
    return num;
}

I get different numbers for all 10 entries when I take the code you posted here and run it in my Chrome console. — SikoSoft
– SikoSoft, Commented Jan 2, 2014 at 12:31
If you are simply returning the variable after assigning, directly return like this return Math.floor((Math.random()*b)+a) — thefourtheye
– thefourtheye, Commented Jan 2, 2014 at 12:32
Math.random is seeded by the current time - what environment are you running it in...? — Emissary
– Emissary, Commented Jan 2, 2014 at 12:41

Lee Taylor · Accepted Answer · 2014-01-02 12:33:26Z

1

Works fine for me:

http://jsfiddle.net/kzUUt/

You need to declare number though...

var number = new Array(10);
for(var i = 0; i < 10; i++)
{
    number[i] = getRandom(0, 100);
    console.log(number[i]);
}

function getRandom(a, b)
{
    var num = Math.floor((Math.random()*b)+a);
    return num;
}

answered Jan 2, 2014 at 12:33

Lee Taylor

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Comments

Zaheer Ahmed · Accepted Answer · 2014-01-02 12:36:41Z

0

Here is working demo.

var number = new Array();
for (var i = 0; i < 10; i++) {
    number[i] = getRandom(0, 100);
}

function getRandom(a, b) {
    return Math.floor((Math.random() * b) + a);   
}
for (var j = 0; j < 10; j++) {
    alert(number[j]);
}

answered Jan 2, 2014 at 12:36

Zaheer Ahmed

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