I have the following doubts in C++. We know that we can initialize the pointer in the time of declaration as follows:
int *p = new int(8)
cout<<*p<<endl;
This will produce the output as 8. Similarly if we declare a pointer to an integer array:
int *p = new int[10];
And this can be initialized as:
p[0] = 7
p[1] = 9;
But is there any way to initialize at the point of declaration?
Using c++11 you can use brace initialization:
int *p = new int[10] { 7, 9 }; // And so on for additional values past the first 2 elements
Yo could use the "{}" as follows:
int main()
{
int *p = new int[10]{1,2,3,4,5,6,7,8,9,10};
cout << p[7] << endl;
return 0;
}
The outoput will be 8, corresponding to the position 7 of the array.
Note: it is a c++11 based solution.
Yes, if you'd like to initialize your array to 1,2,3,4 for example, you can write:
int[] myarray = {1,2,3,4}
new.As other said you can use the C++11 list initialization {}
Or you can overload new [] and initialize with an array, something like following :
#include <iostream>
void* operator new[](std::size_t sz, int *arr)
{
void* p = operator new[](sz);
int *ptr= (int *)p;
std::size_t i=0;
for(;i<sz;++i)
ptr[i] = arr[i];
return p;
}
int main()
{
int arr[] ={1,2,3,4,5,6,7,8};
int* p = new( arr) int[8];
for(int i=0;i<8;i++)
std::cout<<p[i] << std::endl;
delete[] p;
}
