using nested dictionaries in python

Question

I know this question has been asked and I have read through them but I still can't get this to work.

I want to do the following:

bigDict={'AABAA':{'00500':4, '00110':1, '00001':1}, 'AAAAA':{'03300':15, '03110':10, '00401':1}, 'BBBBB':{'11500':1, '11110':1, '11111':1}}

the numbers WITHOUT quotes, 4,1,1,15,10,1,1,1,1 are the COUNTS of those strings which are part of the larger string.

Is this possible in python using nested dictionary? Thank you

I use a sliding window move along a string like AAAABBBBBBLLLLLLAAA and once I find the 5 seq length string for example AABAA, I take that and find the corresponding "number" seq '00500', if I encounter another AABAA then I extract the number seq for that, and if that is again 00500, I now increase the counter for 00500 to 2 from 1

What exactly are you trying to do? Are you generating this dictionary from the larger string you referenced, generating the larger string from this dictionary, something else? — Andrew Clark
– Andrew Clark, Commented Jan 6, 2014 at 19:48
you could use Counters instead of those inner dicts, but appart from that, I have no idea what you are trying to do. — njzk2
– njzk2, Commented Jan 6, 2014 at 19:51
yes exactly, I use a sliding window move along a string like AAAABBBBBBLLLLLLAAA and once I find the 5 seq length string for example AABAA, I take that and find the corresponding "number" seq '00500', if I encounter another AABAA then I extract the number seq for that, and if that is again 00500, I now increase the counter for 00500 to 2 from 1... — Steve Grafton
– Steve Grafton, Commented Jan 6, 2014 at 19:51
I know its valid to have such a structure but I don't know how to create it in python. — Steve Grafton
– Steve Grafton, Commented Jan 6, 2014 at 19:54

jcfollower · Accepted Answer · 2014-01-06 20:18:16Z

1

bigDict = {}

then when you have a letter label and number ...

bigDict.setdefault(label, {}).setdefault(num, 0)
bigDict[label][num] += 1

answered Jan 6, 2014 at 20:18

jcfollower

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