Unix shell script to find a file and replace name by pattern

Question

I have a folder called /input/temp. Inside the folder I have lot of files. I need to find the file of pattern Article_????_test_?????????.txt and replace by format below.

Article_????_?????????.txt

Below is the code I tried and which doesn't work:

echo "Please provide the file name Corresponding to DC..."
read file 
ls $HOME/*.txt | grep $file
if [ $? -eq 0 ]
find . $file '*_Test_*' -exec bash -c 'mv $0 ${0/_Test/ }' {} \;

    if [ $? -eq 0 ]
find . $file -name "*.txt" -exec bash -c "mv {} \`echo {} | sed -e 's/[_TEST_]/_/g'\`" \;
then

I Got below error:

find: 0652-083 Cannot execute bash:: A file or directory in the path name does not exist.
find: 0652-083 Cannot execute bash:: A file or directory in the path name does not exist.

bash can't be executed on my platform.

What shell are you using then? What system is it?

slhck
– slhck

2014-01-08 08:47:23 +00:00
Commented Jan 8, 2014 at 8:47 — slhck
– slhck, Commented Jan 8, 2014 at 8:47

l0b0 · Accepted Answer · 2014-01-08 11:51:34Z

1

Unless the file name is a regular expression you can use if [ -e "$file" ] instead of ls + grep + test.
When you do find . $file '*_Test_*' the last three parameters are actually taken as files or directories to search underneath! It will return
- all files in the current directory,
- all files in the directory $file or the path $file if it's not a directory, and
- all files in any directories matching *_Test_* or their paths if they are not directories.
There's no need for bash - you can run mv directly in -exec. This is just extra complexity for no gain.
Use $(command) instead of command for much easier quote handling. Each $() has a separate quoting context, so you can do for example echo "$(command "$(c2 "argument with spaces")")".

edited Jan 8, 2014 at 11:51

answered Jan 8, 2014 at 11:46

l0b0

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Comments

Vijay · Accepted Answer · 2014-01-08 08:49:14Z

0

According to the link here: This should work

ls -1 Article_????test?????????.txt|awk '{old=$0;gsub(/test/,"_",$0);system("mv \""old"\" "$0)}'

answered Jan 8, 2014 at 8:49

Vijay

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2 Comments

l0b0 Over a year ago

You should not parse ls output like this.

l0b0 Over a year ago

The page linked above explains it.

user414441 · Accepted Answer · 2014-01-08 08:53:59Z

0

Also try the 'rename' command.

rename 's/_test_/_/' *.txt

You can fine tune the regular expression...

answered Jan 8, 2014 at 8:53

user414441

Comments

BMW · Accepted Answer · 2014-01-08 08:59:26Z

0

Update from your code:

cd $HOME
find . -name '*_Test_*' |while read line
do
  echo mv ${line) ${line/_Test/}
done

If you need search the pattern Article_????test?????????.txt, try this

cd $HOME
find . -name 'Article_????_test_?????????.txt' |while read line
do
  echo mv ${line) ${line/_Test/}
done

answered Jan 8, 2014 at 8:59

BMW

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