how to display image from xml through php?

Question

i have two files note.xml and xml.php

here is my code of note.xml

<?xml version="1.0" encoding="ISO-8859-1"?>
<agents>
    <agent>
    <image> img/primary-nav-logo.png</image>
    <name>Tommy Jenkin</name>
    <company>CJenkins Insurance</company>
    <street>Insurance150 S State Stree</street>
    <city>Linkend</city>
    <phone>(773) 561-4331</phone>
    </agent>
    <agent>
    <image> img/primary-nav-logo.png</image>
    <name>Tommy Jenkin</name>
    <company>CJenkins Insurance</company>
    <street>Insurance150 S State Stree</street>
    <city>Linkend</city>
    <phone>(773) 561-4331</phone>
    </agent>
</agents>

and here is my code of xml.php

<?php
                $xml = simplexml_load_file("note.xml") 
                or die("Error: Cannot create object");
                function processXML($node){
                    foreach($node->children() as $agent => $data){
                    if(trim($data) != ""){
                        echo $data;
                        echo "</br>";
                    }
                    else{
                        echo "<hr>";
                    }
                    processXML($data);
                    }
                }  
                processXML($xml);

?>

Now i want to display full data of xml with the image so how can i display it.please help

yes but where i have to place that code and how because you can see i displaying data through just echo $data; — Sanjay Rathod
– Sanjay Rathod, Commented Jan 9, 2014 at 18:40

Krish R · Accepted Answer · 2014-01-09 19:05:11Z

1

Can you try this,

         $xml = simplexml_load_file("note.xml") or die("Error: Cannot create object");
            function processXML($node){
                foreach($node->children() as $agent => $data){      
                      $agent= trim($agent);   
                     if($agent!="" && $agent=='image'){
                           echo '<img src="'.$data.'" >';
                     }elseif($agent!=""){
                          echo $data;
                          echo "</br>";
                     }else{
                          echo "<hr>";
                     }    

                processXML($data);
                }
            }  
            processXML($xml);

edited Jan 9, 2014 at 19:05

answered Jan 9, 2014 at 18:41

Krish R

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5 Comments

Sanjay Rathod Over a year ago

Correct but because of this image is displayed but due to echo $data; the link of image is also displayed so what can i do

Sanjay Rathod Over a year ago

No this is not possible because if we are check for image first and after that for whole data then data can not be print

Sanjay Rathod Over a year ago

Hey do you know how to skip first element from xml fine if yes then my problem can be solved

Sanjay Rathod Over a year ago

yes i had tried this code but as i am saying that if we are trying to check first for image and after that whole data then how it can be possible because the image is part of data not data is a part of image

Krish R Over a year ago

@Sanjay Rathod, I have updated my answer can you please check?

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