getting the arguments (list) of a specific (user defined ) PHP function

Question

is there a way to achieve this in PHP?

echo list_args('a_user_defined_function_name_here_such_as_say_hello');

and this outputs something like

$first_name
$last_name

for a function defined as;

function say_hello($first_name, $last_name){
     echo "Hello $first_name $last_name";
}

So basically, what I'm looking for is a function explainer or something of that sort... & if that thing can get into a php doc based comment extractor. that would be even better..

Look at ReflectionFunction

Wrikken
– Wrikken

2014-01-11 15:11:27 +00:00
Commented Jan 11, 2014 at 15:11 — Wrikken
– Wrikken, Commented Jan 11, 2014 at 15:11

user142162 · Accepted Answer · 2014-01-11 15:11:59Z

3

You could use the ReflectionFunction class to do this:

function list_args($name) {
    $list = "";
    $ref = new ReflectionFunction($name);
    foreach ($ref->getParameters() as $param) {
        $list .= '$' . $param->getName() . "\n"; 
    }
    return $list;
}

answered Jan 11, 2014 at 15:11

user142162

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1 Comment

Average Joe Over a year ago

Thanks Tim.. that really does it... I was at us2.php.net/manual/en/reflection.examples.php page, there I see some more options... But they got their examples based on shell calls. How do I make a piece like $ php --rf strlen work in a PHP page... 5.3+

aksu · Accepted Answer · 2014-01-11 15:13:30Z

1

You can try ReflectionFunction.

function list_args($function) {
    $func = new ReflectionFunction($function);
    $res = array();
    foreach ($func->getParameters() as $argument) {
        $res[] = '$' . $argument->name;   
    }
    return $res;
}

print_r(list_args('say_hello')); // outputs Array ( [0] => $first_name [1] => $last_name )

answered Jan 11, 2014 at 15:13

aksu

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