getting JSON object from a GET cURL in php

Question

Here is my code:

$ch = curl_init('');  

  $request = 'where={"place":"'.$place.'"}&count=1&limit=0';
  $url = "https://api.parse.com/1/classes/className" . "?" . $request;

  curl_setopt($ch, CURLOPT_URL,$url);



  curl_setopt($ch, CURLOPT_HTTPHEADER, array(
    'X-Parse-Application-Id: ...',
    'X-Parse-REST-API-Key: ...
    ));

  //curl_setopt($ch, CURLOPT_POST, true);


  // Execute
  $result = curl_exec($ch);

  // Close connection
  curl_close($ch);

Here is the output:

{"results":[],"count":0}

I want to get only he number in count.

I tried this:

$json_res = json_decode($result, true);

  echo 'Number : '.$json_res['count'];

but the output becomes:

Number :

If i do json_encode the result is just a True value.

I tried added this:

  curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
  curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 2);

but didn't change anything.

What am I missing?

EDIT: doing a var_dump on $json_res gives me that: int(1). Why is that?

Did you bother checking if json_decode() actually succeeded? It returns a php null on failure. — Marc B
– Marc B, Commented Jan 11, 2014 at 22:52
@MarcB hmm, how to check it? Maybe it does not succeed at all. — ghostrider
– ghostrider, Commented Jan 11, 2014 at 22:53
if ($json_res === null) { die(json_last_error()); }. Of course, this can produce a false positive if you really DID send a valid "null" value as the json string. — Marc B
– Marc B, Commented Jan 11, 2014 at 22:55

Alex Barroso · Accepted Answer · 2014-01-11 22:58:13Z

1

Curl does not return the output if you don't set the CURLOPT_RETURNTRANSFER option

curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

answered Jan 11, 2014 at 22:58

Alex Barroso

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