I need javasctript function that writes number of 1 together witch depends on value counter. So if is counter 6 write number 1 six time together.
Here is example output what i need:
var counter = 6;
var output = "111111";
I search forum here...but i have not found any solution how to make this.Any help is welcomed.
Here you have a one-liner
var output = Array(counter + 1).join("1"); //"111" for counter = 3
Cheers
Here is a function that does what you want:
function repeat(letter, count) {
var answer = '';
while(count--) {
answer += letter;
}
return answer;
}
// usage:
var onesixtimes = repeat('1', 6); // '111111'
EDIT:
Completely forgot that ES6 will also have a String.prototype.repeat method:
var s = "1".repeat(6);
This is available right now in Firefox, but a patch is needed for older browsers.
Original answer:
ECMAScript 6 will have a Array.prototype.fill method.
var s = Array(6).fill("1").join("");
You can use it now with a compatibility patch.
Something like this should be close, though perhaps not entirely compatible:
if (!Array.prototype.fill) {
Array.prototype.fill = function(val, start, end) {
start = parseInt(start)
start = isNaN(start) ? 0 :
start < 0 ? Math.max(this.length + start, 0) :
Math.min(this.length, start)
end = parseInt(end)
end = isNaN(end) ? this.length :
end < 0 ? Math.max(this.length + end, 0) :
Math.min(this.length, end)
while (start < end)
this[start++] = val
return this
}
}
Here is a fiddle that shows it working
function writeNum(counter, integer){
var arr = [];
for (var i = 0; i < counter; i++){
arr.push(integer);
}
return arr.join("");
}
forloop