Using array values as array names

Question

I am trying to pass an array value into a function as an arg and then use it's value to reference another array. I know that sounds a bit complicated but I am doing it for a reason ;) I THINK that showProject thinks that project1 is a string as it returns only 'p' and ... Any help appreciated?

var projects = ["project1","project2"];

var project1 = ["image1","image2"];
var project2 = ["image1","image2"];

function showProject(arr){

    console.log(arr[0]);

}

//why isn't this showing image 1 in project 1 array?
showProject(projects[0]);

Fiddle > http://jsfiddle.net/4ryLT/

Yes, you are passing the string "project1" to the function which correclty alerts "p". So what is the question? — Salman Arshad
– Salman Arshad, Commented Jan 13, 2014 at 10:00
why isn't this showing image 1 in project 1 array? because project1 neither project2 are being used inside showProject(). — DontVoteMeDown
– DontVoteMeDown, Commented Jan 13, 2014 at 10:02

A. Wolff · Accepted Answer · 2014-01-13 10:04:04Z

4

This seems to be what you want:

jsFiddle

var project1 = ["image1","image2"];
var project2 = ["image1","image2"];

var projects = [project1,project2];

function showProject(arr){

    alert(arr[0]);

}

showProject(projects[0]);

Set arrays as elements of projects array.

answered Jan 13, 2014 at 10:04

A. Wolff

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1 Comment

timo Over a year ago

My cookies, you took em! ='(

timo · Accepted Answer · 2014-01-13 10:03:31Z

0

is var projects referring to the other two variables? If so, remove the "" and put them in a different order

var project1 = ["image1","image2"];
var project2 = ["image1","image2"];
var projects = [project1,project2];

function showProject(arr){

alert(arr[0]);

}

showProject(projects[0]);

http://jsfiddle.net/4ryLT/3/

answered Jan 13, 2014 at 10:03

timo

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Comments

Frogmouth · Accepted Answer · 2014-01-13 10:12:59Z

0

var projects = ["project1","project2"];

var project1 = ["image1","image2"];
var project2 = ["image1","image2"];

function showProject(arr){

    console.log(eval(arr)[0]);

}

showProject(projects[0]);

edited Jan 13, 2014 at 10:12

Frogmouth

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answered Jan 13, 2014 at 10:02

Alexander Nenkov

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Comments

hsnayd · Accepted Answer · 2014-01-13 10:22:29Z

0

I think you mean this

var projects = [];

projects["project1"] = ["image1","image2"];
projects["project2"] = ["image1","image2"];


function showProject(arr){

   alert(arr[0]);

}

showProject(projects["project1"]);

answered Jan 13, 2014 at 10:22

hsnayd

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Comments

Frogmouth · Accepted Answer · 2014-01-13 10:12:02Z

-1

without change your logic:

var projects = ["project1","project2"];
var project1 = ["image1","image2"];
var project2 = ["image1","image2"];


function showProject(arr){

    console.log(eval(arr)[0]);

}
showProject(projects[0]);

byee

answered Jan 13, 2014 at 10:12

Frogmouth

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2 Comments

Tibos Over a year ago

How is this different than @AlexanderNenkov's answer?

Frogmouth Over a year ago

i see the @AlexanderNenkov after post. Because before my post the AlexanderNenkov answer was "unformatted". if you see i edit the answer and than i see that we write same code... your comment is useless.

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