Incorporating php variable into url with href attribute

Question

I am trying to create the necessary url from this code however it is working and I am struggling to find out why.

$linkere = $row['message'];
echo '<a href="me.php?message=<?php echo rawurlencode($linkere); ?>">'

Currently this code is producing the url: me.php?message= . But, I would like it to create the url: me.php?message=hello for example.

Thanks for helping!

John Conde · Accepted Answer · 2014-01-13 17:29:43Z

2

You are passing $linkere to rawurlencode(). The variable is actually named $linker.

$linker = $row['message'];
echo '<a href="me.php?message=<?php echo rawurlencode($linker); ?>">'

answered Jan 13, 2014 at 17:29

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John Conde

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2 Comments

James Over a year ago

It still doesn't work for some reason - thanks anyway!

the_pete Over a year ago

Your answer still contains the syntax errors that are causing the root issue. There are now three duplicate answers to this questions that solve the issue.

Jorge Faianca · Accepted Answer · 2014-01-13 17:33:48Z

0

You have alot of syntax problems here.

first, you need to use Concatenation message='.rawurlencode($linker).'" second your variable do not exist, it should be $linker.

Second close the tag and insert the text, in this case i used Test.



$linker = $row['message'];
echo '<a href="me.php?message='.rawurlencode($linker).'">Test</a>';

answered Jan 13, 2014 at 17:33

Jorge Faianca

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3 Comments

James Over a year ago

So is this ok: '<a href="me.php?message='.rawurlencode($linkere);'">' . $row['title']. '</a> ' . $row['message'];

Jorge Faianca Over a year ago

No, '.rawurlencode($linkere);'" it should be '.rawurlencode($linkere).'" , notice the "." (dot) after $linkhere)

the_pete Over a year ago

To continue with what Jorge said, the semicolon in your string escape will end the echo entirely. Use this: echo '<a href="me.php?message='.rawurlencode($linkere).'">' . $row['title']. '</a> ' . $row['message'];

Krish R · Accepted Answer · 2014-01-13 17:34:11Z

0

Can you try this,

 $linker = $row['message'];
 echo '<a href="me.php?message='.rawurlencode($linker).'">YOUR LINK TEXT HERE</a>';

answered Jan 13, 2014 at 17:34

Krish R

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Comments

the_pete · Accepted Answer · 2014-01-13 17:47:11Z

0

You don't need the <? ?> and echo in your echo, it should just be:

$linkere = $row['message'];
echo '<a href="me.php?message='.rawurlencode($linkere).'">Test</a>';

Otherwise you are turning php on and off again to echo something within an already open instance of php in which you are already echoing.

edited Jan 13, 2014 at 17:47

answered Jan 13, 2014 at 17:30

the_pete

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2 Comments

James Over a year ago

code echo ' <a href="me.php?message='.rawurlencode($linkere);'">' . $row['title']. '</a> ' . $row['message'];

the_pete Over a year ago

It works for me when I copied and pasted the code back in. I updated the entire section though with your code and more robust link text. Try it now.

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