Java string.match / string.replace does not match regex correctly

Question

I have a string "123.0" and use "123.0".matches( "(\\.)?0*$" ) to check if it has any trailing zeros but it does not match. The same regexp matches string correctly @ http://regexpal.com/

How about if I want to just replace the last zeros with something else. String.replace says:

replace(CharSequence target, CharSequence replacement) - Replaces each substring of this string that matches the literal target sequence with the specified literal replacement sequence.

But "123.0".replace( "(\\.)?0*$", "" ) it will not replace the last ".0".

falsetru · Accepted Answer · 2014-01-15 06:30:30Z

1

The java.lang.String.matches method matches the entire string, not part of it. (No need to specify ^ and $).

So your pattern string should be:

"\\d+\\.?0*"

Demo

UPDATE according to question edit:

You shoudl use replaceAll instead of replace. replace does not accept a regular expression. It interpret the first parameter literally.

"123.0".replaceAll("\\.0*$", "")

edited Jan 15, 2014 at 6:30

answered Jan 15, 2014 at 5:52

falsetru

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1 Comment

markovuksanovic Over a year ago

How about String.replace?

Bohemian · Accepted Answer · 2014-01-15 07:08:44Z

1

Unlike most other languages, java's matches requires the whole string to match, so you'll have to add a leading .* to your regex:

if (str.matches(".*\\.0+"))

Note that your regex seems a bit wrong - everything is optional, so it would match anything. Try this regex instead.

Also, because it had to match the whole string, ^ and $ are implied (code them if you want - it makes no difference)

edited Jan 15, 2014 at 7:08

answered Jan 15, 2014 at 6:07

Bohemian♦

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4 Comments

thefourtheye Over a year ago

This will even match a.0

markovuksanovic Over a year ago

And how about String.replace. I've updated the questions with clarification.

Bohemian Over a year ago

@thefourtheye yes, just as OP's regex would. This regex is the closest to the intent if the code in the question (he's not validating the input, just testing if it ends in zeroes)

Bohemian Over a year ago

@markovuksanovic that's a totally different question. Better to ask a fresh question.

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