PHP Function as a Function's Default Parameter

Question

I was wondering if there is a simpler way that I can use a php inbuilt function as the default value for a function.

Here's my current code:

function custom_date($format = 'm-d-Y', $time = null)
{
    if($format == "d-m-Y") {
        // do something with $time
    }
    return date($format, $time);
}

I want to use time() as a default argument for $time instead of null, but it will not let me. I know I can pass time() as a 2nd argument to custom_date everywhere its called, but it's used at many places without 2nd argument and changing it would be a pain.

AlexP · Accepted Answer · 2014-01-15 23:32:13Z

2

Just force $time to be equal to time() when there has been no value passed to the function.

function custom_date($format = 'm-d-Y', $time = null)
{
    $time = (null == $time) ? time() : $time;
    if($format == "d-m-Y") {
        // do something with $time
    }
    return date($format, $time);
 }

edited Jan 15, 2014 at 23:32

answered Jan 15, 2014 at 23:25

AlexP

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2 Comments

msg7086 Over a year ago

I believe this is what OP really wanted. Give it a default of null, and check if it's null in the function.

msg7086 Over a year ago

Just FYI, > PHP 5.3 You can use $time = $time ?: time();

Mir Adnan · Accepted Answer · 2014-01-16 00:03:09Z

0

Try this.

function custom_date($format = 'm-d-Y', $func = 'time') {
if (function_exists($func)) {
    if ($format == "d-m-Y") {
        // do something with $time
    }
    return date($format, $func());
}elseif(is_numeric($func)){
    //timestamp logic
}}

edited Jan 16, 2014 at 0:03

answered Jan 15, 2014 at 23:24

Mir Adnan

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2 Comments

dhavald Over a year ago

this won't work either as in some cases, I am passing $time argument with timestamp value, and call_user_func(timestamp) would fail

Mir Adnan Over a year ago

@dhavald I just made a few changes to the above code. Hope that helps

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