Parse multiple values in a php string

Question

I am stuck at one point and newbie at regex:

I need to parse a string in php and find out multiple values starting from particular pattern.

But that string which needs to be parsed is actually a javascript code.

This is the string (javascript code) that needs to be parsed :

<script src="http://192.168.1.172/jsScripts/jquery.min.js"></script>
<link rel="stylesheet" 
     type="text/css"  
     href="http://192.168.1.172/adqCss/adqExapandable.css">
<script src="http://192.168.1.172/jsScripts/adqExpandable.js"></script>
<script>
    var t1 = ${kom_demo_test1};
    var t2 = ${kom_demo_test2};
    var url = 'http://demo.com';
</script>

Now i need to identify all words that start with ${kom_dom_ and then i want to store test1 , test2 in an array .

Any help is appreciated.

Thanks in advance :)

Will you parse that in PHP or Javascript?

Stefano Sanfilippo
– Stefano Sanfilippo

2014-01-16 11:36:18 +00:00
Commented Jan 16, 2014 at 11:36 — Stefano Sanfilippo
– Stefano Sanfilippo, Commented Jan 16, 2014 at 11:36
I will parse it in PHP

WomenInTech
– WomenInTech

2014-01-16 11:58:52 +00:00
Commented Jan 16, 2014 at 11:58 — WomenInTech
– WomenInTech, Commented Jan 16, 2014 at 11:58

Community · Accepted Answer · 2023-11-17 20:24:57Z

1

You can do that quite easily using preg_match_all, something like this:

<?php
$input= '<script src="http://192.168.1.172/jsScripts/jquery.min.js"></script>
<link rel="stylesheet" 
     type="text/css"  
     href="http://192.168.1.172/adqCss/adqExapandable.css">
<script src="http://192.168.1.172/jsScripts/adqExpandable.js"></script>
<script>
    var t1 = ${kom_demo_test1};
    var t2 = ${kom_demo_test2};
    var url = \'http://demo.com\';
</script>';

$matches= array(); // An array to store the results
$results= preg_match_all('/\${kom_demo_(.*)}/', $input, $matches);

var_dump($matches);

Which will produce:

array
  0 => 
    array
      0 => string '${kom_demo_test1}' (length=17)
      1 => string '${kom_demo_test2}' (length=17)
  1 => 
    array
      0 => string 'test1' (length=5)
      1 => string 'test2' (length=5)

So $matches[1] contains the results you are looking for.

edited Nov 17, 2023 at 20:24

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answered Jan 16, 2014 at 11:40

Clart Tent

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Comments

Flosculus · Accepted Answer · 2014-01-16 11:40:49Z

1

This is an expression that will work for this. Capture group 1 will give you everything after kom_demo_.

/\$\{kom_demo_([^\}]+)\}/

answered Jan 16, 2014 at 11:40

Flosculus

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