PHP - Adding echo statement into a link array

Question

I'm trying to modify a link array in php to add a variable at the end of a link. I thought this was a very easy thing to do, but I keep erroring out when I do it. I'm not sure if I am missing syntax or if it is not possible to do it the way I am doing it.

Here is the array without any modifications and it works fine

$links[]=array(
"url"=>'?p=worksheet', // this is one way I tried, I also added ''
'name'=>'Worksheet',   // This is where the name I want displayed goes
'order'=>999999,
);
}

The variable I am trying to add is $cust_id

This is how I am trying to add it:

$links[]=array(
"url"=>'?p=worksheet'<?php echo $cust_id ;?>, // this is one way I tried, I also added ''
'name'=>'Worksheet',   
'order'=>999999,
);
}

Marc B · Accepted Answer · 2014-01-17 02:42:03Z

2

echo does output at the moment you call it. You're trying to concatenate two strings. And you also cannot embed PHP code within PHP code. Try

'url' => '?p=worksheet' . $cust_id,
                       ^^^^^^^^^^^

instead.

edited Jan 17, 2014 at 2:42

answered Jan 17, 2014 at 2:28

Marc B

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4 Comments

Marc B Over a year ago

sorry, should've been a , at the end, not ;.

Michael Falciglia Over a year ago

I thought you meant that so I tried it both ways. It omits the variable altogether when I do that

Marc B Over a year ago

Not possible. The only possibility is that $cust_id is not properly set. THis would generate '?p=worksheet42', if $cust_id was 42.

Michael Falciglia Over a year ago

I thought maybe it was not set, I will try to test it out by just adding something in the page to see if it is set.

rm-vanda · Accepted Answer · 2014-01-17 02:34:22Z

1

Use a concatenation operator: (of your choice):

$links = array(
"url"=>'?p=worksheet'.$cust_id, 
'name'=>'Worksheet{$cust_id}',   
'doubleQuotes'= "Make variables render $cust_id",
'finally' => $pre-tailored-variable;
);

where the last one would be have to made ahead of time:

$pre-tailored-variable = "String of some kind with value:".$value;

answered Jan 17, 2014 at 2:34

rm-vanda

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2 Comments

Michael Falciglia Over a year ago

The way I am doing it, I think maybe my variable did not set correctly, is that what you mean by your answer?

rm-vanda Over a year ago

The variable, or the array? You don't need the square brackets for defining an associative array --- but if $cust_id is set, then any of the above methods will suffice for adding its value into the array--

Dan H · Accepted Answer · 2014-01-17 02:29:05Z

0

You can't inline functions like this in PHP...

$links[0]['url'] = '?p=worksheet' . $cust_id;

Might be what you're after.

answered Jan 17, 2014 at 2:29

Dan H

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Comments

cyberwombat · Accepted Answer · 2014-01-17 02:29:20Z

0

$links[]=array(
 "url"=>'?p=worksheet'.$cust_id,

answered Jan 17, 2014 at 2:29

cyberwombat

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