Combine output in single line using echo in a batch file

Question

I want to modify the below script to give me out put like

Number of processes on machine1 are 1

Number of processes on machine2 are 3

Number of processes on machine3 are 7

Number of processes on machine4 are 2

Please can someone help?

===============================

@echo off
setlocal enabledelayedexpansion

pushd "%~dp0"

echo %date% %time% 

TASKLIST /S machine1 | grep -c "process" 
TASKLIST /S machine2 | grep -c "process" 
TASKLIST /S machine3 | grep -c "process" 
TASKLIST /S machine4 | grep -c "process"

================================

Please edit your code for readability. E.g. indent any code by four spaces. Then, it is highlighted in gray. — Mathias Müller
– Mathias Müller, Commented Jan 17, 2014 at 19:51

mihai_mandis · Accepted Answer · 2017-06-06 18:37:30Z

1

You can use the filter if IMAGENAME command to give you just the necessary processes. I used a for command because output of IMAGENAME behaves strange...it is always displayed at the beginning of the line.

@echo off 
set compName1=machine1
for /f %%a in ('tasklist /NH /FO CSV /FI "IMAGENAME eq process" ^| find /C /V ""') do (
    echo Number of processes on %compName1% are %%a
)

edited Jun 6, 2017 at 18:37

answered Jan 17, 2014 at 19:51

mihai_mandis

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