How we can call javascript function from code-behind in asp.net?

Question

I have this javascript function :

function showLoader() {
           document.getElementById("loaderState").style.display = 'inline';
       }

And I have a button :

<asp:Button ID="btnSignUp" runat="server" Text="Sign Up" OnClick="btnSignUp_Click" />

I am tryong to call that js function in code behind :

protected void btnSignUp_Click(object sender, EventArgs e)
{
    try
    {
        int i = users.AddNewUser();
        if (i != 0)
        {
            Page.ClientScript.RegisterStartupScript(
                GetType(),
                "btnSignUp",
                "showLoader();",
                true);
        }
    }
    catch (Exception exp)
    {
        throw exp;
    }
}

But not worked!!! Why?
Thanks.

Have you tried to comment everything in btnSignUp_Click, then add just this line: Page.ClientScript.RegisterStartupScript(GetType(), "btnSignUp", "showLoader();", true); ? Maybe it's because the i value is 0 — ekad
– ekad, Commented Jan 18, 2014 at 13:12
possible duplicate of Execute javascript function after asp.net postback without Ajax — Amir
– Amir, Commented Jan 18, 2014 at 18:47
i was used update panel. if use onclientclick="showLoader()" it work fine, but if call it from code behind it does not work. — Farzaneh Talebi
– Farzaneh Talebi, Commented Jan 18, 2014 at 19:09

Community · Accepted Answer · 2017-05-23 12:29:16Z

2

Use:

 ScriptManager.RegisterStartupScript(
 this,
 GetType(), 
"btnSignUp",
"showLoader();",
 true);

See these similar question:

ScriptManager.RegisterStartupScript code not working - why?

ClientScript.RegisterStartupScript not working

ScriptManager.RegisterStartUpScript(...) not working

edited May 23, 2017 at 12:29

CommunityBot

11 silver badge

answered Jan 18, 2014 at 12:59

user1968030

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Comments

Somnath · Accepted Answer · 2014-01-18 12:58:28Z

1

Try This

protected void btnSignUp_Click(object sender, EventArgs e)
{
    try
    {
        int i = users.AddNewUser();
        if (i != 0)
        {
ScriptManager.RegisterStartupScript(this, GetType(), "btnSignUp", "showLoader()", true);

        }
    }
    catch (Exception exp)
    {
        throw exp;
    }
}

answered Jan 18, 2014 at 12:58

Somnath

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