Print binary then negate without ones complement in python

Question

i'm new to python and tried to do something like that:

a=23
"{0:b}".format(a)

---> '10111'

then i want to negate it WITHOUT ones complement, the result should be '01000' but nothing seems to work

secondly i would have to fill up the left side with 0's, i found something like

"{0:12b}".format(a)
'       10111'

but it just makes the string longer filling it up with blanks

EDIT: the perfect solution for me would be

"{0:12b}".format(a)
'000000010110' 
"{0:12b}".format(~a)
'111111101001'

(which of course doesnt work this way)

eduffy · Accepted Answer · 2014-01-21 13:33:25Z

3

Put a 0 in front of the 12 to left-pad the output with zeroes.

In [1]: "{0:012b}".format(a)
Out[1]: '000000010111'

For the ones comp, the you could do string manipulation, or the math way:

 In [2]: "{0:012b}".format(2**12-1-a)
 Out[2]: '111111101000'

Just change the 2**12 to the number of digits you want to display

answered Jan 21, 2014 at 13:33

eduffy

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3 Comments

Stefan Over a year ago

yes that worked thanks, you have a solution for my other (main) problem too?

Corley Brigman Over a year ago

for one's comp of a specific length, you can also use xor: 0xfff ^ num.

eduffy Over a year ago

2**12 is 1 followed 12 zeroes. Subtract 1 and you get 12 ones. Subtracting anything from all ones switches the bits. 1-1=0 and 1-0=1. Basically it's doing the xor operation that @CorleyBrigman describes.

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