PHP readfile() URL issue

Question

I have a url like this:

http://r16---sn-4g57kn6e.googlevideo.com/videoplayback?&quality=medium&signature=797C0FEB1961E6226294D5FC19BC0CD28657975C.1E745D852200D14B706F0EBF9EA8762680374564&itag=43&mv=m&ip=84.19.165.220&ipbits=0&ms=au&ratebypass=yes&source=youtube&mt=1390347607&id=8b92b07ff9cd9862&key=yt5&fexp=942502,916626,929305,936112,924616,936910,936913,907231,921090&upn=cMPazwtmyZU&sver=3&sparams=id,ip,ipbits,itag,ratebypass,source,upn,expire&expire=1390371882&type=video%2Fwebm%3B+codecs%3D%22vp8.0%2C+vorbis%22&fallback_host=tc.v12.cache5.googlevideo.com&title=Requiem+For+A+Dream+Original+Song&title=Requiem For A Dream Original Song

The problem is that the readfile() function produces a error cause of the special characters (bad request).

If i use urlencode() it ruins the url even more.

How can i handle this?

Awesome track BTW. Now I have to drink myself to sleep again though — PeeHaa
– PeeHaa, Commented Jan 21, 2014 at 23:57
Oh yeah it is. I listen to it since 4 hours (repeat function). It's very good while coding :D — TheNiceGuy
– TheNiceGuy, Commented Jan 21, 2014 at 23:58
Nope that does not help. My question has nothing todo with that persons one. — TheNiceGuy
– TheNiceGuy, Commented Jan 21, 2014 at 23:59
Don't urlencode the whole string, just the song title? Have you tried using file_get_contents instead? — Dan H
– Dan H, Commented Jan 22, 2014 at 0:03

Brad · Accepted Answer · 2014-01-22 00:09:07Z

1

You simply need to urlencode() the data in you use in the querystring. In your post, you have not escaped the last variable. Do not urlencode() the whole URL.. that would not be proper.

http://r16---sn-4g57kn6e.googlevideo.com/videoplayback?&quality=medium&signature=797C0FEB1961E6226294D5FC19BC0CD28657975C.1E745D852200D14B706F0EBF9EA8762680374564&itag=43&mv=m&ip=84.19.165.220&ipbits=0&ms=au&ratebypass=yes&source=youtube&mt=1390347607&id=8b92b07ff9cd9862&key=yt5&fexp=942502,916626,929305,936112,924616,936910,936913,907231,921090&upn=cMPazwtmyZU&sver=3&sparams=id,ip,ipbits,itag,ratebypass,source,upn,expire&expire=1390371882&type=video%2Fwebm%3B+codecs%3D%22vp8.0%2C+vorbis%22&fallback_host=tc.v12.cache5.googlevideo.com&title=Requiem+For+A+Dream+Original+Song&title=Requiem For A Dream Original Song

I would just use http_build_query() instead.

echo 'http://r16---sn-etc' . http_build_query(array(
    'ip' => 84.19.165.220,
    'ipbits' => 0,
    // etc.
    'title' => 'Requiem for a Dream'
));

answered Jan 22, 2014 at 0:09

Brad

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4 Comments

TheNiceGuy Over a year ago

Sorry i can't follow you. Can you please post a example? As i said above i encoded everything except the http://. Even without the titel it is not working.

Brad Over a year ago

@Michael Right, you're encoding more than you should be.

Floris Over a year ago

@Michael see my updated answer for an "automatically built" url / query string. And Brad : +1 for pointing to http_build_query().

Brad Over a year ago

@Michael Of course you can build the URL yourself... And, you needn't build the entire thing, just the parts you need. Leave the rest as-is.

Floris · Accepted Answer · 2014-01-22 04:54:50Z

Combining things I had in my original answer, plus some of the ideas in Brad's answer, I offer the following solution

<?php
$url='http://r16---sn-4g57kn6e.googlevideo.com/videoplayback?&quality=medium&signature=797C0FEB1961E6226294D5FC19BC0CD28657975C.1E745D852200D14B706F0EBF9EA8762680374564&itag=43&mv=m&ip=84.19.165.220&ipbits=0&ms=au&ratebypass=yes&source=youtube&mt=1390347607&id=8b92b07ff9cd9862&key=yt5&fexp=942502,916626,929305,936112,924616,936910,936913,907231,921090&upn=cMPazwtmyZU&sver=3&sparams=id,ip,ipbits,itag,ratebypass,source,upn,expire&expire=1390371882&type=video%2Fwebm%3B+codecs%3D%22vp8.0%2C+vorbis%22&fallback_host=tc.v12.cache5.googlevideo.com&title=Requiem+For+A+Dream+Original+Song&title=Requiem For A Dream Original Song';
$cleanUrl = parseQuery($url);
$data = getData($cleanUrl);
echo "file read in OK\n";

function parseQuery($url) {
  preg_match('/(https?:\/\/[^?]+\?)(.*)$/', $url, $rawQuery);
  preg_match_all('/([^=]+)=([^&]+)&/', $rawQuery[2], $queries);
  $qArray = array_combine($queries[1], $queries[2]);
  $newUrl = $rawQuery[1] . http_build_query($qArray);
  return $newUrl;
}

function getData($url) {
$useragent="Mozilla/5.0 (Windows; U; Windows NT 5.1; en-US; rv:1.8.1.1) Gecko/20061204 Firefox/2.0.0.1";

$curl = curl_init();
curl_setopt($curl, CURLOPT_URL, $url);
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, false);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($curl, CURLOPT_USERAGENT, $useragent);
$data = curl_exec($curl);
curl_close($curl);
return $data;
}
?>

This basically involves the following steps:

Take the initial URL, and split it into "stuff before the ?, and stuff after"
The "stuff before" is untouched; the "stuff after" is split into two array - the keys and the values of the query ("everything up to =", and "everything up to &")
These two arrays are then combined into a valid query string using (from Brad's answer) the http_build_query array
Finally, I use curl to fetch the file (just because I know it better than readfile()).

It appears to work for me. Let me know if it doesn't work for you...

No it has nothing to do with the useragent. The problem is the format of the url. curl_exec(): 23 is not a valid cURL handle resource

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