Json.NET deserializing object returns null

Question

I would like to deserialize a string o JSON and output data on a string:

public class Test
{
    public int id { get; set; }
    public string name { get; set; }
    public long revisionDate { get; set; }
}

private void btnRetrieve_Click(object sender, EventArgs e)
{
    string json = @"{""Name"":{""id"":10,""name"":""Name"",""revisionDate"":1390293827000}}";
    var output = JsonConvert.DeserializeObject<Test>(json);
    lblOutput.Text = output.name;
}

This is intended to output the name property of the string json. However, it returns nothing.

Mauro Cerutti · Accepted Answer · 2014-01-22 12:11:53Z

9

The JSON you posted can be deserialized into an object which has a Name propery of type Test, not into a Test instance.

This

string json = @"{""id"":10,""name"":""Name"",""revisionDate"":1390293827000}";

would be a representation of a Test instance.

Your JSON may be deserialized into something like this:

public class Test
{
   public int id { get; set; }
   public string name { get; set; }
   public long revisionDate { get; set; }
}

public class Foo
{
    public Test Name { get; set; }
}

// ...


var output = JsonConvert.DeserializeObject<Foo>(json);
lblOutput.Text = output.Name.name;

edited Jan 22, 2014 at 12:11

answered Jan 22, 2014 at 12:01

Mauro Cerutti

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1 Comment

theMayer Over a year ago

Adding to this, it sometimes helps to drop your JSON into a visualizer tool to see these sorts of things jump out at you: jsoneditoronline.org

Mukesh Methaniya · Accepted Answer · 2017-01-06 07:21:32Z

0

Valid json for Test class is below

{ "Name": { "id": 10, "name": "Name", "revisionDate": 1390293827000 } }

and Also your json is in containg more data then only test class so you can also use like

Dictionary<string,Test> dictionary= JsonConvert.DeserializeObject<Dictionary<string,Test>>(json);

Test oputput=dictionary["Name"];

answered Jan 6, 2017 at 7:21

Mukesh Methaniya

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