I want sort values by array Another
for example
var objName = [{id:1, name:"one"},{id:2, name:"two"}, {id:3, name:"three"}];
var sortById = [1,3,2];
I want this output in that order
1 one
3 three
2 two
-
2Can we see your unsuccessful attempts?Ram– Ram2014-01-24 00:51:53 +00:00Commented Jan 24, 2014 at 0:51
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4 Answers
Stuff objName elements into a hash (i.e. object) indexed by id, then map the sortById array onto the hash values.
Exact code left as an exercise for the reader.
sorted=new Array()
for(var id_index=0;id_index<sortById.length;id_index++)
{
for(var obj_index=0;obj_index<objName.length;obj_index++){
if (objName[obj_index].id===sortById[id_index]) sorted.push(objName[obj_index])
}
}
//now sorted is the new sorted array. if you want to overwrite the original object:
objName=sorted;
1 Comment
Kenneth
Won't work, he wants to sort by id. Who says the ids are in the correct order in the first array?
Supposing that the length of both arrays are the same you can first create a hash:
var objName = [{id:1, name:"one"},{id:2, name:"two"}, {id:3, name:"three"}];
var myHash = {};
for(var i = 0; i<objName.length;i++){
myHash[objName[i].id] = objName[i];
}
Once you have this hash, you can loop over your keys array and get the values out:
var sortById = [1,3,2];
var sortedArray = [];
for(var i = 0; i<sortById.length;i++){
sortedArray.push(myHash[sortById[i]]);
}
Comments
Something clear and readable (subjective, probably not for everyone):
var result = [];
sortById.forEach(function(id) {
result = result.concat(objName.filter(function(i) {
return i.id == id;
}));
});
JSFiddle: http://jsfiddle.net/RLH6F/
Implemented just for fun.
Warning: O(n^2)
PS: I agree it would be better just give the recipe without the code, but as soon as there are already community members provided the copy-paste solutionы I decided to provide at least a nice looking one.
