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I have ajax call:

$.ajax({
        type: "POST",
        url: "../getFormMetaData/",
        cache:false,
        data: $data,
        success: createZoomDialog,
        error:function(response){

        }
    });

how can I send data to ajax error handler from python django?

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  • Just send 4xx or 5xx status code on response, js will route it into error callback. Commented Jan 24, 2014 at 13:04

1 Answer 1

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You can return HttpResponse with a 4xx error code in your view:

def view(request):
    return HttpResponse("error", status=404)
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