Storing string in numpy matrix

Question

I create the following:

a=np.eye(2, dtype='S17')

But when I print it I get:

print(a)
[[b'1' b'']
 [b'' b'1']]

Why does it happen and what I can do to just get the strings without b? Or should I change the way of introducing the data or the dtype?

The desired output would be:

[['1' '']
 ['' '1']]

So that I can replace this strings by others

Because I want to store strings there, therefore when I create the matrix I first say what type of data I will put inside and then add it. — llrs
– llrs, Commented Jan 24, 2014 at 18:42

Ashwini Chaudhary · Accepted Answer · 2014-01-24 18:49:44Z

2

You can use numpy.char.decode to decode the bytes literal:

In [1]: import numpy as np

In [2]: a = np.eye(2, dtype='S17')                                                                                   

In [3]: a
Out[3]: 
array([[b'1', b''],                                                                                                
       [b'', b'1']],                                                                                               
      dtype='|S17')                                                                                                

In [4]: np.char.decode(a, 'ascii')                                                                                 
Out[4]: 
array([['1', ''],                                                                                                  
       ['', '1']],                                                                                                 
      dtype='<U1')

answered Jan 24, 2014 at 18:49

Ashwini Chaudhary

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1 Comment

llrs Over a year ago

Instead of dtype='S17' changing it to '<U1' produces the same effect thanks!

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