Using npm commands to start NodeJS project with arguments

Question

I am trying to create two separate npm commands to start my NodeJS project locally on the dev machine and in production mode. I want to be able to pass arguments to the machine separately to serve the right dependencies - which could be a CDN in production OR my local machine.

Here's what I am looking to have in package.json

"run": "node ./server/app.js", /* for running locally*/

"start": "node ./server/app.js", /* for running in production*/

If I try to call npm run - it creates this error:

npm ERR! npm run-script [<pkg>] <command>
npm ERR! not ok code 0

I also want to be able to send commandline argumentswhich would contain a URL.

Ali · Accepted Answer · 2014-01-25 08:53:55Z

5

You are not doing it right.

To call custom scripts, you have to run

npm run-script run

Your package.json should have:

"scripts": {
    "start": "node ./server/app.js",
    "run": "node ./server/app.js"
}

See: https://npmjs.org/doc/cli/npm-run-script.html

answered Jan 25, 2014 at 8:53

Ali

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Climenty · Accepted Answer · 2015-06-24 16:13:02Z

0

You can use this bash script to run any (even nested) module directly with arguments. Don't forget to change ~/Develop/node_modules to your local path.

#!/bin/bash
if [ $# -eq 0 ]; then
    echo Usage: npmrun module [args]
    exit
fi
data=~/bin/npmrun.data
if [ -f $data ]; then source $data
else declare -A where
fi
cd ~/Develop/node_modules
if [ -z ${where[$1]} ]; then
    path=$(find -path '*/bin/'$1)
    if [ -z $path ]; then
        echo "Module \"$1\" not founded!"
        exit
    else
        where[$1]=$path;
        declare -p where > $data
    fi
fi
${where[$1]} ${@:2}

answered Jun 24, 2015 at 16:13

Climenty

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