PHP: Convert $_POST into variable?

Question

I'm building a form that's in a loop, so that the user can choose how many rows they want to put into the database. And all my input-names have this value art_$i where $i is the number of the rows, that my loop generates.

When the form-button is pressed, I then try to pull out the value of each $_POST['art_X'] by creating a second loop that repeats itself the same amount of times as my $i loop that is naming by inputs as art_1, art_2, art_3 etc. This second loop I call $b, here's how I try to solve the problem.. It just isn't working at all!

$convert_post_to_variable = "$_POST[art_" . $b . "]";

Any suggestions on how I could solve this problem, would be MUCH APPRECIATED! :-D

Your description is cryptic to me. More code would be a help. The line you posted $convert_post_to_variable = "$_POST[art_" . $b . "]"; creates a string variable with the contents "$_POST..." - that is probably not what you want (remove the outside quotes. — Rid Iculous
– Rid Iculous, Commented Jan 25, 2014 at 23:46

Brad · Accepted Answer · 2014-01-25 23:45:48Z

1

Don't use quotes around variable names. It makes a mess of things, and then you would have to use curly brackets... just don't do it. You can use an arbitrary string key on an associative array like this:

$convert_post_to_variable = $_POST['art_' . $b];

answered Jan 25, 2014 at 23:45

Brad

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darthmaim · Accepted Answer · 2014-01-25 23:46:01Z

0

Use the following code:

$convert_post_to_variable = $_POST[ 'art_' . $b ];

answered Jan 25, 2014 at 23:46

darthmaim

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