PHP prepend an array

Question

By using the PHP below outputs the values underneath. But because I don't have control of the API output I would like to try and prepend the data with another output such as {"id":0,"name":"Begin","description":"this is my description","url":"http://domain.com"}

Could someone please help?

PHP

<?php
$jsonurl = "/api/styles";
$json = file_get_contents($jsonurl);

echo $json;
?>

OUTPUTS

[{"id":1,"name":"Pale","description":"this is my description","url":"http://domain.com"},{"id":2,"name":"Dawn","description":"this is my description","url":"http://domain.com"}]

This is json, not a PHP array. Is it supposed to be converted into a PHP array, or do you just want to prepend your own json to the json from the API? — jd182
– jd182, Commented Jan 26, 2014 at 15:37
@jd182 I'd like to add that json to the front of the printed — ngplayground
– ngplayground, Commented Jan 26, 2014 at 15:38
As I understand, you want to prepend your data in order to "sanitize" to some extent the output of the API you can't control, right? — Axel Amthor
– Axel Amthor, Commented Jan 26, 2014 at 15:40

reformed · Accepted Answer · 2014-01-26 15:42:15Z

1

Is this what you have in mind?

<?php
$jsonurl = "/api/styles";
$json = file_get_contents($jsonurl);
$json = '[{"id":0,"name":"Begin","description":"this is my description","url":"http://domain.com"},' . substr($json, 1);
echo $json;
?>

Output:

[{"id":0,"name":"Begin","description":"this is my description","url":"http://domain.com"},{"id":1,"name":"Pale","description":"this is my description","url":"http://domain.com"},{"id":2,"name":"Dawn","description":"this is my description","url":"http://domain.com"}]

answered Jan 26, 2014 at 15:42

reformed

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1 Comment

Axel Amthor Over a year ago

The OPs title is misleading. This is simple string concatenation.

Alexander Mohorev · Accepted Answer · 2014-01-26 15:52:50Z

1

$jsonurl = "/api/styles";
$json = file_get_contents($jsonurl);
$begin = '{"id":0,"name":"Begin","description":"this is my description","url":"http://domain.com"}';

$data = json_decode($json);
array_unshift($data, json_decode($begin));

echo json_encode($data);

answered Jan 26, 2014 at 15:52

Alexander Mohorev

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Comments

EricSchaefer · Accepted Answer · 2014-01-26 15:37:09Z

0

If it really is json, parse it (decode_json()) and print it anyway you like.

answered Jan 26, 2014 at 15:37

EricSchaefer

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Comments

Hayden · Accepted Answer · 2014-01-26 15:50:38Z

0

I'm not exactly certain what you're wanting to "prepend" but you can turn it into a PHP array, reverse it then push new elements onto the array.

$json = file_get_contents($jsonurl);
$array = json_decode($json, true);
$reversed = array_reverse( $array );
$reversed[] = ['id' => 0, 'name' => 'Something];

Reverse it back and encode it.

answered Jan 26, 2014 at 15:50

Hayden

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