splitting the outerHTML attribute in python

Question

I would want to split out particular text from the outerHTML attribute for a web link.

while Id is true:
    link = driver.find_element_by_xpath("//a[@id='bu:ms:all-sp:2']")
    href = link.get_attribute("outerHTML")  
    link.click()
    # This will load the link in the same page !
    self.assertIn(href, self.page.get_current_url())

When I print the href, output would be,

<a id="bu:ms:all-sp:8" href="/euro/tennis" class="Pointer"><span class="SportImg8"></span> Tennis <span class="NumEvt">51</span></a>

I would want to split this and assert the value of href alone (/euro/tennis) with the current URL.

Could anyone please help me out here ?

falsetru · Accepted Answer · 2014-01-27 08:24:24Z

3

Get href attribute instead of outerHTML:

href = link.get_attribute("href")

answered Jan 27, 2014 at 8:24

falsetru

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