Java JSON Deserialization Error

Question

I have the following code that uses Java JSON:

Widget w = new Widget(true, "LIVE");
WidgetService service = new WidgetServiceImpl();    // 3rd party JSON web service

JSONObject response = service.postWidget(w);

System.out.println("Response is: " + response.toString());
System.out.println("Now fetching orderid...");
System.out.println(response.getString("order_id"));

Don't worry about Widget or WidgetService: this question has to do with how I'm using the Java JSON API (and specifically JSONObject).

When I run the above code, I get:

Response is: {"response":{"credits_used":"0.30","job_count":1,"order_id":"243050","currency":"USD"},"opstat":"ok"}
Now fetching orderid...
Exception in thread "main" org.json.JSONException: JSONObject["order_id"] not found.
    at org.json.JSONObject.get(JSONObject.java:473)
    at org.json.JSONObject.getString(JSONObject.java:654)
    at com.me.myapp.MyDriver.main(MyDriver.java:49)

As you can see, there is an order_id String field coming back in the response, and it has a value of "243050". So why am I getting the exception?

the orderid is not directly linked to the response object, it is within another object — epoch
– epoch, Commented Jan 27, 2014 at 14:15

Max Fichtelmann · Accepted Answer · 2014-01-27 14:15:19Z

2

Your JSONObject response points to the outer json object.

I am pretty sure, your response object has a property "response" (and "opstat" btw.) containing your expected object.

answered Jan 27, 2014 at 14:15

Max Fichtelmann

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2 Comments

AdjustingForInflation Over a year ago

Thanks @Max Fichtelmann (+1) - so what do I need to do to fix it?

Max Fichtelmann Over a year ago

JSONObject#getJSONObject(String) should get the inner response Object, just like @dstronczak said.

dstronczak · Accepted Answer · 2014-01-27 14:19:25Z

0

You have to do it like this:

response.getJSONObject("response").getString("order_id");

answered Jan 27, 2014 at 14:19

dstronczak

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