How to compare a multidimensional array with one array element?

Question

I have a multidimensional array as follows,

$array1 = Array(
            'id'       => Array(1 => 19, 2 => 47),
            'name'     => Array(1 => 'Alex Paul', 21 => 'sdfs'),
            'category' => Array(1 => 1, 21 => 2)
             );

Also I have an array element

     $res['id'][1]= 47;

I want to check $res['id'][1] is present in $array1 or not. How to solve this issue

this looks all to be php, why is javascript tagged?

Patrick Evans
– Patrick Evans

2014-01-28 05:23:19 +00:00
Commented Jan 28, 2014 at 5:23 — Patrick Evans
– Patrick Evans, Commented Jan 28, 2014 at 5:23

Alireza Fallah · Accepted Answer · 2014-01-28 05:42:16Z

1

Just use in_array function

if(in_array($res['id'][1], $array1['id']))
    echo 'Here';

edited Jan 28, 2014 at 5:42

Alireza Fallah

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answered Jan 28, 2014 at 5:32

Mario

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Comments

Community · Accepted Answer · 2023-11-17 19:52:31Z

1

You can check using in_array() in php

  if(in_array($res['id'][1],$array1['id'])) {
      echo $res['id'][1] . ' exist in array';
  } else {
     echo 'not exist';

  }

Working Demo

edited Nov 17, 2023 at 19:52

CommunityBot

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answered Jan 28, 2014 at 5:25

Roopendra

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3 Comments

Alireza Fallah Over a year ago

you are just checking in the $array1['id']

Roopendra Over a year ago

If I am think logically, then OP compare with $res['id'][1] which is id so I have not consider whole array and just check with id.

Alireza Fallah Over a year ago

you are right, but the question does not mention comparing with just id,

Adil Abbasi · Accepted Answer · 2014-01-28 05:37:46Z

0

Try like,

   $array1=Array ( 'id' => Array (  1 => 19, 2 => 47 ),
           'name' => Array ( 1 => 'Alex Paul', 21 => 'sdfs' ),
           'category' => Array ( 1 => 1, 21 => 2 ));

   $res['id'][1]= 47;

   if(in_array($res['id'][1], $array1['id']))
     echo 'found';

answered Jan 28, 2014 at 5:37

Adil Abbasi

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Comments

Alireza Fallah · Accepted Answer · 2014-01-28 05:46:18Z

0

This checks that $res['id'][1] is present in the whole $array1 or not :

$present = false;
foreach($array1 as $val){
    if(in_array($res['id'][1],$val)) $present = true;
}
echo $present ? "Yes" : "No";

If you just want to check in $array1['id'][1], as the other answers are saying,

it is as simple as this :

echo in_array($res['id'][1],$array1['id'][1]) ? "Yes" : "No" ;

Documentation of in_array()

edited Jan 28, 2014 at 5:46

answered Jan 28, 2014 at 5:34

Alireza Fallah

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